编程实现: 1、创建列表: ['spring','summer',autumn, wi nter'] 2、反转列表并输出 3、获取列表长度并输出 4、在列表尾部添加'season” 5、使用pop将列表中的'autumn'删掉,并输出列表 6、使用del删除列表中索引为1的元素,并输出列表 7、用加号连接两个列表
时间: 2023-05-11 17:06:05 浏览: 37
1. 列表创建代码如下:
seasons = ['spring', 'summer', 'autumn', 'winter']
2. 反转列表并输出:
seasons.reverse()
print(seasons)
输出结果为:['winter', 'autumn', 'summer', 'spring']
3. 获取列表长度并输出:
print(len(seasons))
输出结果为:4
4. 在列表尾部添加'season':
seasons.append('season')
print(seasons)
输出结果为:['winter', 'autumn', 'summer', 'spring', 'season']
5. 使用pop将列表中的'autumn'删掉,并输出列表:
seasons.pop(1)
print(seasons)
输出结果为:['winter', 'summer', 'spring', 'season']
6. 使用del删除列表中索引为1的元素,并输出列表:
del seasons[1]
print(seasons)
输出结果为:['winter', 'spring', 'season']
7. 用加号连接两个列表:
list1 = ['a', 'b', 'c']
list2 = ['d', 'e', 'f']
new_list = list1 + list2
print(new_list)
输出结果为:['a', 'b', 'c', 'd', 'e', 'f']
相关问题
输入一个1-4的数字,输出该整数对应的季度的英文单词,季度英文单词分别为:spring、summer、autumn、winrer
ChatGPT:Sure, I can help you with that. Here is the code:
```python
def get_season(num):
if num == 1:
return "spring"
elif num == 2:
return "summer"
elif num == 3:
return "autumn"
elif num == 4:
return "winter"
else:
return "Invalid input. Please enter a number between 1 and 4."
number = input("Please enter a number between 1 and 4: ")
print(get_season(int(number)))
```
Please note that this code can only handle input values between 1 and 4, and will output an error message for any other values.
c++输出将整数1~4转换为对应的4个季节。例如:1、2、3、4对应spring,summer,autumn,winter。输入1~4以外的数,则输出“data error”。
#include <stdio.h>
int main() {
int num;
printf("请输入1~4中的一个数字:");
scanf("%d", &num);
switch (num) {
case 1:
printf("spring\n");
break;
case 2:
printf("summer\n");
break;
case 3:
printf("autumn\n");
break;
case 4:
printf("winter\n");
break;
default:
printf("data error\n");
break;
}
return 0;
}