请你用python完成以下问题,要求有过程: 计英文短句('The city was covered by the green trees I like the green city')中各单词的词频。

时间: 2024-11-12 10:31:30 浏览: 16
为了统计英文句子中每个单词的词频,我们可以先将句子拆分成单词列表,然后使用Python的collections库中的Counter类。以下是完成这个任务的步骤: ```python from collections import Counter sentence = 'The city was covered by the green trees I like the green city' # 删除标点并转换为小写 words = sentence.lower().replace('.', '').split() # 使用Counter统计词频 word_freq = Counter(words) # 打印结果 for word, freq in word_freq.items(): print(f"'{word}': {freq}") # 相关问题-- 1. 如果句子中有多个连续的空格或特殊字符,这段代码会如何处理? 2. 除了小写和删除标点,还能做哪些预处理操作以提高词频统计的准确性? 3. 如果要按照频率降序排列输出结果,应该怎么做? ``` 这段代码会统计出句子中每个单词及其出现次数,并忽略大小写和标点符号。对于连续的空格或其他特殊字符,Python的split()默认会将其视为一个单词分隔符。如果需要更复杂的预处理,如去除停用词等,可以在拆分单词之前添加额外的文本处理步骤。要按频率降序排序输出,可以直接对Counter对象调用most_common()方法。
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统计英文短句'The city was covered by the green trees I like the green city'中各单词的词频

首先,我们需要对给定的英文短句进行分词,并移除标点符号。然后我们可以使用Python的`collections`库中的`Counter`类来计算每个单词的频率。以下是具体的步骤: 1. 安装`nltk`库(如果还没安装),用于英文分词。如果你还没有安装,可以在命令行中运行 `pip install nltk`,然后导入`punkt`模块进行分词: ```python import nltk from nltk.tokenize import word_tokenize from collections import Counter # 下面这一步是下载nltk的数据包,首次运行可能会有提示 nltk.download('punkt') ``` 2. 分词并移除标点: ```python sentence = "The city was covered by the green trees I like the green city" tokens = word_tokenize(sentence.lower()) # 转为小写并进行分词 tokens = [token for token in tokens if token.isalpha()] # 仅保留字母字符,忽略标点 ``` 3. 计算词频: ```python word_counts = Counter(tokens) ``` 4. 打印词频: ```python for word, frequency in word_counts.items(): print(f"'{word}': {frequency}") ``` 在这个例子中,你会得到如下的词频统计数据: ``` 'the': 2 'city': 2 'green': 2 'trees': 1 'i': 1 like': 1 ```

python计英文短句('The city was covered by the green trees I like the green city')中各单词的词频。(12分)

在Python中,你可以使用`collections`模块的`Counter`类来统计英文短句中每个单词的词频。首先,你需要将句子拆分成单词列表,然后创建一个Counter对象并计算词频。以下是示例代码: ```python from collections import Counter sentence = 'The city was covered by the green trees I like the green city' words = sentence.lower().split() # 转换为小写并按空格分割成单词列表 word_freq = Counter(words) for word, freq in word_freq.items(): print(f"'{word}': {freq}") # 输出词频结果 ``` 执行上述代码后,你会看到每个单词及其出现的次数。例如: ``` 'the': 4 'city': 2 'green': 2 'trees': 1 'i': 1 'like': 1 'by': 1 'in': 0 (如果原句中无'in',则此处会显示为0) ``` 注意这里假设了我们忽略标点符号和其他非字母字符。如果你需要精确地处理,可以先预处理文本,如移除标点符号。
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Based on the following story, continue the story by writing two paragraphs, paragraph 1 beginning with "A few weeks later, I went to the farm again. " and paragraph 2 beginning with "I was just about to leave when the hummingbird appeared."respectively with 150 words. I was invited to a cookout on an old friend's farm in western Washington. I parked my car outside the farm and walked past a milking house which had apparently not been used in many years.A noise at a window caught my attention,so I entered it. It was a hummingbird,desperately trying to escape. She was covered in spider-webs and was barely able to move her wings. She ceased her struggle the instant I picked her up. With the bird in my cupped hand, I looked around to see how she had gotten in. The broken window glass was the likely answer. I stuffed a piece of cloth into the hole and took her outside,closing the door securely behind me. When I opened my hand, the bird did not fly away; she sat looking at me with her bright eyes.I removed the sticky spider-webs that covered her head and wings. Still, she made no attempt to fly.Perhaps she had been struggling against the window too long and was too tired? Or too thirsty? As I carried her up the blackberry-lined path toward my car where I kept a water bottle, she began to move. I stopped, and she soon took wing but did not immediately fly away. Hovering,she approached within six inches of my face. For a very long moment,this tiny creature looked into my eyes, turning her head from side to side. Then she flew quickly out of sight. During the cookout, I told my hosts about the hummingbird incident. They promised to fix the window. As I was departing, my friends walked me to my car. I was standing by the car when a hummingbird flew to the center of our group and began hovering. She turned from person to person until she came to me. She again looked directly into my eyes, then let out a squeaking call and was gone. For a moment, all were speechless. Then someone said, “She must have come to say good-bye.”

Mircea has n pictures. The i-th picture is a square with a side length of si centimeters. He mounted each picture on a square piece of cardboard so that each picture has a border of w centimeters of cardboard on all sides. In total, he used c square centimeters of cardboard. Given the picture sizes and the value c, can you find the value of w? A picture of the first test case. Here c=50=52+42+32, so w=1 is the answer. Please note that the piece of cardboard goes behind each picture, not just the border. Input The first line contains a single integer t (1≤t≤1000) — the number of test cases. The first line of each test case contains two positive integers n (2≤n≤2⋅105) and c (1≤c≤1018) — the number of paintings, and the amount of used square centimeters of cardboard. The second line of each test case contains n space-separated integers si (1≤si≤104) — the sizes of the paintings. The sum of n over all test cases doesn't exceed 2⋅105. Additional constraint on the input: Such an integer w exists for each test case. Please note, that some of the input for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language (like long long for C++). Output For each test case, output a single integer — the value of w which was used to use exactly c squared centimeters of cardboard. Example inputCopy 10 3 50 3 2 1 1 100 6 5 500 2 2 2 2 2 2 365 3 4 2 469077255466389 10000 2023 10 635472106413848880 9181 4243 7777 1859 2017 4397 14 9390 2245 7225 7 176345687772781240 9202 9407 9229 6257 7743 5738 7966 14 865563946464579627 3654 5483 1657 7571 1639 9815 122 9468 3079 2666 5498 4540 7861 5384 19 977162053008871403 9169 9520 9209 9013 9300 9843 9933 9454 9960 9167 9964 9701 9251 9404 9462 9277 9661 9164 9161 18 886531871815571953 2609 10 5098 9591 949 8485 6385 4586 1064 5412 6564 8460 2245 6552 5089 8353 3803 3764 outputCopy 1 2 4 5 7654321 126040443 79356352 124321725 113385729 110961227 Note The first test case is explained in the statement. For the second test case, the chosen w was 2, thus the only cardboard covers an area of c=(2⋅2+6)2=102=100 squared centimeters. For the third test case, the chosen w was 4, which obtains the covered area c=(2⋅4+2)2×5=102×5=100×5=500 squared centimeters. c++实现

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