1!+2!+3!+...+10!编程python
时间: 2023-11-24 18:51:09 浏览: 78
以下是Python代码,用于计算1!+2!+3!+...+10!的和:
```python
sum = 0
for i in range(1, 11):
sum1 = 1
for n in range(1, i + 1):
sum1 = sum1 * n
sum = sum + sum1
print(sum)
```
输出结果为:4037913
相关问题
计算1!+2!+3!+...+n!编程python
以下是Python代码:
```
n = int(input("请输入一个整数n:"))
factorial = 1
sum = 0
for i in range(1, n+1):
factorial *= i
sum += factorial
print("1! + 2! + 3! + ... + n! =", sum)
```
运行结果:
```
请输入一个整数n:5
1! + 2! + 3! + ... + n! = 153
```
解释:当n=5时,计算1! + 2! + 3! + 4! + 5! = 1 + 2 + 6 + 24 + 120 = 153。
编程计算1!+2!+3!+...+10!【要求:1. 首先定义阶乘计算函数,然后定义求和函数;2. 结果使用format输出1!+2!+3!+...+10!=4037913】
以下是Python代码实现:
```python
def fact(n):
"""计算n的阶乘"""
result = 1
for i in range(2, n+1):
result *= i
return result
def sum_fact(n):
"""计算1!+2!+3!+...+n!"""
sum = 0
for i in range(1, n+1):
sum += fact(i)
return sum
result = sum_fact(10)
print("1!+2!+3!+...+10!={}".format(result))
```
输出结果为:1!+2!+3!+...+10!=4037913
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