删除这个表的重复行：df_teacher_leader_retire.reset_index()[["姓名","年龄", "最高学历", "岗位级别","工作量"]]

要删除DataFrame中的重复行，可以使用`drop_duplicates()`方法。根据你提供的代码，可以按照以下方式进行操作：

df_teacher_leader_retire.reset_index()[["姓名","年龄", "最高学历", "岗位级别","工作量"]].drop_duplicates()

这将返回一个新的DataFrame，其中不包含重复的行。

相关问题

补全Account和FreeChecking类的实现 class Account: """An account has a balance and a holder. >>> a = Account('John') >>> a.deposit(12) 12 >>> a.balance 12 >>> a.interest 0.02 >>> a.time_to_retire(20) 26 >>> a.balance # balance 保持不变 12 >>> a.withdraw(11) # 每次取款额度不超过10，超过无法取出 "Can't withdraw that amount" >>> a.withdraw(10) 2 >>> a.withdraw(10) 'Insufficient funds' """ def __init__(self, account_holder): def deposit(self, amount): def withdraw(self, amount): def time_to_retire(self, amount): """Return the number of years until balance would grow to amount.""" assert self.balance > 0 and amount > 0 and self.interest > 0 class FreeChecking(Account): """A bank account that charges for withdrawals, but the first two are free! >>> ch = FreeChecking('Jack') >>> ch.balance = 20 >>> ch.withdraw(100) # 首次取款免费，不论是否成功，免费次数减少1次 'Insufficient funds' >>> ch.withdraw(3) # 第二次取款免费 17 >>> ch.balance 17 >>> ch.withdraw(3) # 2次免费用完，开始收费 13 >>> ch.withdraw(3) 9 >>> ch2 = FreeChecking('John') >>> ch2.balance = 10 >>> ch2.withdraw(3) # 首次免费 7 >>> ch.withdraw(3) # 2次免费 5 >>> ch.withdraw(5) # 余额不足 'Insufficient funds' """ def __init__(self, account_holder): def withdraw(self, amount): import doctest doctest.testmod()

class Account:
"""An account has a balance and a holder.
>>> a = Account('John')
>>> a.deposit(12)
12
>>> a.balance
12
>>> a.interest
0.02
>>> a.time_to_retire(20)
26
>>> a.balance # balance 保持不变
12
>>> a.withdraw(11) # 每次取款额度不超过10，超过无法取出
"Can't withdraw that amount"
>>> a.withdraw(10)
2
>>> a.withdraw(10)
'Insufficient funds'
"""
def __init__(self, account_holder):
self.holder = account_holder
self.balance = 0
self.interest = 0.02

def deposit(self, amount):
self.balance += amount
return self.balance

def withdraw(self, amount):
if amount > 10:
return "Can't withdraw that amount"
elif self.balance < amount:
return 'Insufficient funds'
else:
self.balance -= amount
return self.balance

def time_to_retire(self, amount):
assert self.balance > 0 and amount > 0 and self.interest > 0
years = 0
while self.balance < amount:
self.balance *= (1 + self.interest)
years += 1
return years

class FreeChecking(Account):
"""A bank account that charges for withdrawals, but the first two are free!
>>> ch = FreeChecking('Jack')
>>> ch.balance = 20
>>> ch.withdraw(100) # 首次取款免费，不论是否成功，免费次数减少1次
'Insufficient funds'
>>> ch.withdraw(3) # 第二次取款免费
17
>>> ch.balance
17
>>> ch.withdraw(3) # 2次免费用完，开始收费
13
>>> ch.withdraw(3)
9
>>> ch2 = FreeChecking('John')
>>> ch2.balance = 10
>>> ch2.withdraw(3) # 首次免费
7
>>> ch.withdraw(3) # 2次免费
5
>>> ch.withdraw(5) # 余额不足
'Insufficient funds'
"""
def __init__(self, account_holder):
super().__init__(account_holder)
self.free_withdrawals = 2
self.withdrawal_fee = 1

def withdraw(self, amount):
if self.free_withdrawals > 0:
self.free_withdrawals -= 1
return super().withdraw(amount)
else:
return super().withdraw(amount + self.withdrawal_fee)

import doctest
doctest.testmod()

某公司有两类职员Employee和Manager，Manager是一种特殊的Employee。每个Employee对象所具有的基本信息为：姓名、年龄、工作年限、部门号；Manager对象除具有上述基本信息外，还具有级别(level)信息。公司中的Employee和Manager都具有以下两种基本操作，请根据上述描述，用C++语言定义并实现类Employee和Manager。 a．insert Info（）//实现对象信息的输入 b．printOn() // 输出对象的基本信息（姓名、年龄、工作年限、部门号、在职情况） c. retire() // 判断是否到了退休年龄，是，表明在职情况为退休。公司规定： // Employee类对象的退休年龄为55岁，Manager类对象的退休年龄为60岁 编程要求： 1、定义并实现类Employee和Manager 2、按照年龄降序模式分别输出公司中两类人员的人员情况（注意：Manager对象也是Employee对象）。

以下是一个可能的解决方案：

#include <iostream>
#include <string>
using namespace std;

class Employee {
protected:
    string name;
    int age;
    int workYears;
    int deptNo;
    bool retired;

public:
    Employee() {
        name = "";
        age = 0;
        workYears = 0;
        deptNo = 0;
        retired = false;
    }

    virtual void insertInfo() {
        cout << "请输入姓名：";
        cin >> name;
        cout << "请输入年龄：";
        cin >> age;
        cout << "请输入工作年限：";
        cin >> workYears;
        cout << "请输入部门号：";
        cin >> deptNo;
    }

    virtual void printOn() {
        cout << "姓名：" << name << endl;
        cout << "年龄：" << age << endl;
        cout << "工作年限：" << workYears << endl;
        cout << "部门号：" << deptNo << endl;
        cout << "在职情况：" << (retired ? "退休" : "在职") << endl;
    }

    virtual void retire() {
        if (age >= 55) {
            retired = true;
        }
    }
};

class Manager : public Employee {
private:
    int level;

public:
    Manager() : Employee() {
        level = 0;
    }

    void insertInfo() override {
        Employee::insertInfo();
        cout << "请输入级别：";
        cin >> level;
    }

    void printOn() override {
        Employee::printOn();
        cout << "级别：" << level << endl;
    }

    void retire() override {
        if (age >= 60) {
            retired = true;
        }
    }
};

int main() {
    const int MAX_EMPLOYEES = 100;
    Employee* employees[MAX_EMPLOYEES];
    int numEmployees = 0;

    // 输入Employee和Manager对象信息
    cout << "请输入Employee和Manager对象信息：" << endl;
    char ch;
    do {
        cout << "请输入员工类型（E代表Employee，M代表Manager）：";
        cin >> ch;
        if (ch == 'E' || ch == 'e') {
            employees[numEmployees] = new Employee();
        } else if (ch == 'M' || ch == 'm') {
            employees[numEmployees] = new Manager();
        } else {
            cout << "无效输入，请重新输入！" << endl;
            continue;
        }
        employees[numEmployees]->insertInfo();
        numEmployees++;
        cout << "是否继续输入？（Y代表是，N代表否）：";
        cin >> ch;
    } while (ch == 'Y' || ch == 'y');

    // 输出Employee对象信息
    cout << "按照年龄降序模式输出Employee对象信息：" << endl;
    for (int i = 0; i < numEmployees; i++) {
        if (dynamic_cast<Employee*>(employees[i]) != nullptr) {
            employees[i]->retire();
        }
    }
    for (int i = 0; i < numEmployees; i++) {
        for (int j = i + 1; j < numEmployees; j++) {
            if (dynamic_cast<Employee*>(employees[i]) != nullptr &&
                dynamic_cast<Employee*>(employees[j]) != nullptr &&
                employees[i]->age < employees[j]->age) {
                Employee* temp = employees[i];
                employees[i] = employees[j];
                employees[j] = temp;
            }
        }
    }
    for (int i = 0; i < numEmployees; i++) {
        if (dynamic_cast<Employee*>(employees[i]) != nullptr) {
            employees[i]->printOn();
            cout << endl;
        }
    }

    // 输出Manager对象信息
    cout << "按照年龄降序模式输出Manager对象信息：" << endl;
    for (int i = 0; i < numEmployees; i++) {
        if (dynamic_cast<Manager*>(employees[i]) != nullptr) {
            employees[i]->retire();
        }
    }
    for (int i = 0; i < numEmployees; i++) {
        for (int j = i + 1; j < numEmployees; j++) {
            if (dynamic_cast<Manager*>(employees[i]) != nullptr &&
                dynamic_cast<Manager*>(employees[j]) != nullptr &&
                employees[i]->age < employees[j]->age) {
                Employee* temp = employees[i];
                employees[i] = employees[j];
                employees[j] = temp;
            }
        }
    }
    for (int i = 0; i < numEmployees; i++) {
        if (dynamic_cast<Manager*>(employees[i]) != nullptr) {
            employees[i]->printOn();
            cout << endl;
        }
    }

    // 释放内存
    for (int i = 0; i < numEmployees; i++) {
        delete employees[i];
    }

    return 0;
}

在这个例子中，我们定义了两个类：Employee和Manager，其中Manager是Employee的子类。Employee类和Manager类都实现了insertInfo()、printOn()和retire()三个方法。其中，insertInfo()用于输入对象信息，printOn()用于输出对象信息，retire()用于判断对象是否到了退休年龄。需要注意的是，由于Manager类是Employee类的子类，因此Manager类中可以直接调用Employee类中的方法，不需要重新实现。

在主函数中，我们首先输入Employee和Manager对象信息，并按照年龄降序模式分别输出公司中两类人员的人员情况。在输出之前，我们需要先调用retire()方法判断对象是否到了退休年龄，然后按照年龄降序对对象进行排序。在排序时，我们使用了dynamic_cast运算符来区分Employee对象和Manager对象。

最后，我们需要记得释放动态分配的内存。