统计字符出现次数c语言pta
时间: 2023-12-10 15:04:28 浏览: 63
以下是统计字符出现次数的C语言代码:
```c
#include <stdio.h>
#include <string.h>
int main() {
int m, i, j, number, max;
char a[10000], b;
scanf("%d", &m);
getchar();
while (m--) {
a[10000] = {};
scanf("%s", a);
getchar();
for (i = 0, max = 0, b = a[i]; a[i] != '\0'; i++) {
for (j = 0, number = 1; a[j] != '\0'; j++)
if (a[i] == a[j] && j != i)
number++;
if ((number > max) + (number == max && a[i] < b) > 0) {
b = a[i];
max = number;
}
}
printf("%c %d\n", b, max);
}
return 0;
}
```
相关问题
统计字符pta+c语言
以下是统计字符pta+c语言的代码示例:
```c
#include <stdio.h>
#include <ctype.h>
#include <string.h>
int main()
{
char str[1001];
int count[26] = {0};
int max = 0;
char maxChar;
fgets(str, 1001, stdin);
int len = strlen(str);
for (int i = 0; i < len; i++)
{
if (isalpha(str[i]))
{
count[tolower(str[i]) - 'a']++;
}
}
for (int i = 0; i < 26; i++)
{
if (count[i] > max)
{
max = count[i];
maxChar = i + 'a';
}
}
printf("%c %d", maxChar, max);
return 0;
}
```
字符串逆序c语言pta
以下是一个使用C语言实现字符串逆序的例子:
```c
#include <stdio.h>
#include <string.h>
int main() {
char str[100];
gets(str);
int i, n;
n = strlen(str);
char* p = str + n - 1;
for (i = 0; i < n; i++) {
printf("%c", *p);
p--;
}
return 0;
}
```
输入样例:
Hello World!
输出样例:
!dlroW olleH