select CASE WHEN d.OFFICE_TYPE = '0' AND c.OFFICE_TYPE = '21' THEN c.OFFICE_TYPE WHEN d.OFFICE_TYPE = '21' THEN d.OFFICE_TYPE ELSE '1' END AS OFFICE_TYPE FROM (SELECT ID,PARENT_ID,OFFICE_TYPE FROM SYS_OFFICE) c RIGHT JOIN ( SELECT COALESCE(b.PARENT_ID, '0') as PARENT_ID, CASE WHEN a.OFFICE_TYPE = '21' THEN a.OFFICE_TYPE WHEN b.OFFICE_TYPE = '21' THEN b.OFFICE_TYPE ELSE '0' END AS OFFICE_TYPE FROM (SELECT ID,PARENT_ID,OFFICE_TYPE FROM SYS_OFFICE) a LEFT JOIN ( SELECT ID ,PARENT_ID,OFFICE_TYPE FROM SYS_OFFICE) b ON a.PARENT_ID = b.ID WHERE a.ID = 'CA6437DB5A18451CAEA74D2FDA63BDA6' ) d ON c.ID = d.PARENT_ID WHERE d.PARENT_ID is not null ; 优化一下
时间: 2024-04-19 11:24:19 浏览: 4
对于这段SQL查询语句的优化,可以考虑以下几个方面:
1. 索引优化:确保SYS_OFFICE表中的ID、PARENT_ID和OFFICE_TYPE列都有适当的索引,以提高查询的性能。
2. 子查询简化:可以将子查询合并或简化为更简洁的形式,减少查询的复杂度。例如,可以使用JOIN操作来代替子查询。
3. 使用INNER JOIN:根据查询的需求,可以将RIGHT JOIN改为INNER JOIN,以减少查询的结果集大小。
4. 减少CASE WHEN语句:根据实际需求,可以尽量减少CASE WHEN语句的嵌套和判断条件,以简化查询逻辑。
5. 优化WHERE条件:根据数据分布情况,可以对WHERE条件进行优化,尽量选择索引列作为过滤条件。
具体的优化策略需要根据实际数据和查询需求来决定,可以通过分析执行计划和性能测试来评估优化效果,并根据具体情况进行调整和改进。
相关问题
select a.id,SUM(CASE WHEN d.shoukuan_month = '2023-05' and d.is_del = 0 then d.netincome ELSE 0 end) as one_shoukuan,SUM(CASE WHEN d.shoukuan_month = '2023-04' AND d.is_del = 0 THEN d.netincome ELSE 0 END) as two_shoukuan,(CASE WHEN b.month = '2023-05' THEN b.create_income ELSE 30000 END) as one_income,(CASE WHEN b.month = '2023-04' THEN b.create_income ELSE 30000 END) as two_income from a left join b on b.kefuid = a.id left join d on d.kefuid = a.id where a.brand = '1' and a.is_del = 0 and a.is_lizhi = 0 group by a.id这个sql如何让select 中的d.one_shoukuan >= b.one_income and d.two_shoukuan >= b.two_income这个多个join会导致sum多次循环导致sum不断叠加
你可以在外层使用HAVING子句来过滤结果集,而不是在WHERE子句中使用条件。因为HAVING子句是在分组完成后对聚合结果进行筛选的。这样可以避免SUM函数多次循环导致的重复计算。修改后的SQL如下:
```
SELECT
a.id,
SUM(CASE WHEN d.shoukuan_month = '2023-05' and d.is_del = 0 THEN d.netincome ELSE 0 END) as one_shoukuan,
SUM(CASE WHEN d.shoukuan_month = '2023-04' AND d.is_del = 0 THEN d.netincome ELSE 0 END) as two_shoukuan,
(CASE WHEN b.month = '2023-05' THEN b.create_income ELSE 30000 END) as one_income,
(CASE WHEN b.month = '2023-04' THEN b.create_income ELSE 30000 END) as two_income
FROM a
LEFT JOIN b ON b.kefuid = a.id
LEFT JOIN d ON d.kefuid = a.id
WHERE a.brand = '1' and a.is_del = 0 and a.is_lizhi = 0
GROUP BY a.id
HAVING
SUM(CASE WHEN d.shoukuan_month = '2023-05' and d.is_del = 0 THEN d.netincome ELSE 0 END) >= (CASE WHEN b.month = '2023-05' THEN b.create_income ELSE 30000 END)
AND SUM(CASE WHEN d.shoukuan_month = '2023-04' AND d.is_del = 0 THEN d.netincome ELSE 0 END) >= (CASE WHEN b.month = '2023-04' THEN b.create_income ELSE 30000 END)
```
Select(`ifnull(sum(CASE WHEN b.asid=a.link_id and a.user_type=? then b.sum_order_amt else 0 end),0) as sum_pay_amt, ifnull(sum(CASE WHEN b.asid=a.link_id and a.user_type=? then 1 else 0 end),0) as order_sum, ifnull(sum(CASE WHEN a.stmt_status=1 THEN a.profit ELSE 0 END), 0.00) as sum_profit, ifnull(sum(CASE WHEN a.stmt_status=0 and b.asid=a.link_id and a.user_type=? THEN a.pay_amt+b.sum_order_amt ELSE 0 END), 0.00) as ret_pay_amt`, model.USER_TYPE_SUPPLIER_AGENT, model.USER_TYPE_SUPPLIER_AGENT, model.USER_TYPE_SUPPLIER_AGENT).
这段代码是一个SQL查询语句,使用了`SELECT`关键字来选择多个字段。具体的查询内容如下:
- `ifnull(sum(CASE WHEN b.asid=a.link_id and a.user_type=? then b.sum_order_amt else 0 end),0) as sum_pay_amt`:计算满足条件的`b.sum_order_amt`的总和,如果没有满足条件的记录,则返回0。
- `ifnull(sum(CASE WHEN b.asid=a.link_id and a.user_type=? then 1 else 0 end),0) as order_sum`:计算满足条件的记录数,如果没有满足条件的记录,则返回0。
- `ifnull(sum(CASE WHEN a.stmt_status=1 THEN a.profit ELSE 0 END), 0.00) as sum_profit`:计算`a.profit`字段的总和,但仅针对`a.stmt_status`等于1的记录进行计算,如果没有满足条件的记录,则返回0.00。
- `ifnull(sum(CASE WHEN a.stmt_status=0 and b.asid=a.link_id and a.user_type=? THEN a.pay_amt+b.sum_order_amt ELSE 0 END), 0.00) as ret_pay_amt`:计算满足条件的`a.pay_amt+b.sum_order_amt`字段的总和,但仅针对`a.stmt_status`等于0、`b.asid=a.link_id`和`a.user_type=?`的记录进行计算,如果没有满足条件的记录,则返回0.00。
这些查询字段将作为结果的列,并分别命名为`sum_pay_amt`、`order_sum`、`sum_profit`和`ret_pay_amt`。其中,`?`是一个占位符,用于将`model.USER_TYPE_SUPPLIER_AGENT`的值填充到查询中。