c语言设计算法求二叉树所包含的叶结点的数目。
时间: 2024-06-13 08:06:32 浏览: 23
以下是C语言设计算法求二叉树所包含的叶结点的数目的代码实现:
```c
#include <stdio.h>
#include <stdlib.h>
// 定义二叉树结构体
struct TreeNode {
int val;
struct TreeNode *left;
struct TreeNode *right;
};
// 计算二叉树叶子节点数目的函数
int countLeafNodes(struct TreeNode* root) {
if (root == NULL) {
return 0;
}
if (root->left == NULL && root->right == NULL) {
return 1;
}
return countLeafNodes(root->left) + countLeafNodes(root->right);
}
int main() {
// 构建二叉树
struct TreeNode* root = (struct TreeNode*)malloc(sizeof(struct TreeNode));
root->val = 1;
root->left = (struct TreeNode*)malloc(sizeof(struct TreeNode));
root->left->val = 2;
root->left->left = NULL;
root->left->right = NULL;
root->right = (struct TreeNode*)malloc(sizeof(struct TreeNode));
root->right->val = 3;
root->right->left = (struct TreeNode*)malloc(sizeof(struct TreeNode));
root->right->left->val = 4;
root->right->left->left = NULL;
root->right->left->right = NULL;
root->right->right = (struct TreeNode*)malloc(sizeof(struct TreeNode));
root->right->right->val = 5;
root->right->right->left = NULL;
root->right->right->right = NULL;
// 计算叶子节点数目并输出
int count = countLeafNodes(root);
printf("The number of leaf nodes in the binary tree is: %d\n", count);
return 0;
}
```
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