一个只有0和1的数组转16进制字符串

以下是Python代码实现：

def binary_to_hex(binary):
    # 检查二进制数组长度是否为4的倍数
    if len(binary) % 4 != 0:
        binary = [0] * (4 - (len(binary) % 4)) + binary
    # 将二进制数组转换为16进制字符串
    hex_str = ''
    for i in range(0, len(binary), 4):
        hex_digit = 8 * binary[i] + 4 * binary[i+1] + 2 * binary[i+2] + binary[i+3]
        hex_str += hex(hex_digit)[2:]
    return hex_str.upper()

示例：

>>> binary = [1, 0, 1, 0, 1, 1, 0, 0, 1, 0, 1, 1, 0, 0, 0, 1]
>>> binary_to_hex(binary)
'A58C1'