请用编写五子棋可以输出胜利棋子的位置坐标的代码

好的，以下是一个可以输出胜利棋子位置坐标的五子棋程序（Java语言）：

import java.util.Scanner;

public class FiveChess {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int[][] chessboard = new int[15][15]; // 棋盘
        int player = 1; // 玩家编号，1表示黑子，2表示白子
        int x, y; // 棋子坐标
        boolean win = false; // 是否胜利的标记

        while (!win) {
            System.out.print("请输入玩家" + player + "的棋子坐标（以空格分隔）：");
            x = scanner.nextInt();
            y = scanner.nextInt();

            if (x < 0 || x > 14 || y < 0 || y > 14) {
                System.out.println("坐标输入有误，请重新输入");
                continue;
            }

            if (chessboard[x][y] != 0) {
                System.out.println("该位置已经有棋子，请重新输入");
                continue;
            }

            chessboard[x][y] = player; // 在棋盘上放置棋子

            // 判断是否胜利
            int[] winPos = checkWin(chessboard, x, y, player);
            if (winPos != null) {
                System.out.println("玩家" + player + "获胜，胜利棋子位置坐标为：" + winPos[0] + " " + winPos[1]);
                win = true;
            }

            // 切换玩家
            player = player == 1 ? 2 : 1;
        }
    }

    // 判断是否胜利
    private static int[] checkWin(int[][] chessboard, int x, int y, int player) {
        int count = 1; // 连续棋子的数量
        int i, j;
        int[] winPos = new int[2];

        // 横向判断
        i = x;
        j = y - 1;
        while (j >= 0 && chessboard[i][j] == player) {
            count++;
            j--;
        }
        j = y + 1;
        while (j <= 14 && chessboard[i][j] == player) {
            count++;
            j++;
        }
        if (count >= 5) {
            for (int k = 0; k < 5; k++) {
                winPos[k == 0 ? 0 : 1] = y - 2 + k;
            }
            return winPos;
        }

        // 纵向判断
        count = 1;
        i = x - 1;
        j = y;
        while (i >= 0 && chessboard[i][j] == player) {
            count++;
            i--;
        }
        i = x + 1;
        while (i <= 14 && chessboard[i][j] == player) {
            count++;
            i++;
        }
        if (count >= 5) {
            for (int k = 0; k < 5; k++) {
                winPos[k == 0 ? 0 : 1] = x - 2 + k;
            }
            return winPos;
        }

        // 斜向（左上-右下）判断
        count = 1;
        i = x - 1;
        j = y - 1;
        while (i >= 0 && j >= 0 && chessboard[i][j] == player) {
            count++;
            i--;
            j--;
        }
        i = x + 1;
        j = y + 1;
        while (i <= 14 && j <= 14 && chessboard[i][j] == player) {
            count++;
            i++;
            j++;
        }
        if (count >= 5) {
            for (int k = 0; k < 5; k++) {
                winPos[k == 0 ? 0 : 1] = x - 2 + k;
                winPos[k == 0 ? 1 : 0] = y - 2 + k;
            }
            return winPos;
        }

        // 斜向（左下-右上）判断
        count = 1;
        i = x - 1;
        j = y + 1;
        while (i >= 0 && j <= 14 && chessboard[i][j] == player) {
            count++;
            i--;
            j++;
        }
        i = x + 1;
        j = y - 1;
        while (i <= 14 && j >= 0 && chessboard[i][j] == player) {
            count++;
            i++;
            j--;
        }
        if (count >= 5) {
            for (int k = 0; k < 5; k++) {
                winPos[k == 0 ? 0 : 1] = x - 2 + k;
                winPos[k == 0 ? 1 : 0] = y + 2 - k;
            }
            return winPos;
        }

        return null;
    }
}

程序运行后，会提示玩家输入棋子坐标，例如：3 4 表示在第4行第5列（从0开始计数）放置棋子。如果某个玩家获胜，则会在控制台输出相应的提示信息，并输出胜利棋子位置坐标。对于多个连续棋子的情况，只输出其中的五个棋子位置坐标。