Using swap file "conf/.nginx.conf.swp" Original file "/usr/local/nginx/conf/nginx.conf" E308: Warning: Original file may have been changed Recovery completed. You should check if everything is OK. (You might want to write out this file under another name and run diff with the original file to check for changes) You may want to delete the .swp file now
时间: 2024-04-27 09:19:38 浏览: 6
这是 Vim 编辑器所提示的一段信息,它表示在编辑 `/usr/local/nginx/conf/nginx.conf` 文件时,Vim 检测到存在一个名为 `.nginx.conf.swp` 的交换文件,这通常是由 Vim 在编辑文件时自动生成的。当 Vim 意外退出或崩溃时,这个交换文件可以帮助恢复之前编辑的内容。这个提示告诉我们,可能有其他进程或用户已经修改了原始文件,因此我们需要检查一下交换文件和原始文件的差异,以确保没有丢失任何重要的更改。如果一切正常,我们可以删除这个交换文件。
相关问题
/etc/nginx/conf.d/default.conf 配置文件怎么写
很抱歉,由于引用[1]提到的问题描述不完整,无法提供关于"/etc/nginx/conf.d/default.conf"配置文件的具体写法。请提供更详细的问题描述,以便我可以帮助你更好地解决问题。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
#### 引用[.reference_title]
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[ .reference_list ]
https://codeforces.com/contest/1809/problem/C
The problem statement can be found at Codeforces website.
Approach:
Let's start by looking at some examples:
- 1, 2, 3, 4, 5 → No moves needed.
- 2, 1, 3, 5, 4 → One move needed: swap index 1 and 2.
- 5, 4, 3, 2, 1 → Two moves needed: swap index 1 and 5, then swap index 2 and 4.
We can observe that in order to minimize the number of moves, we need to sort the array in non-descending order and keep track of the number of swaps we make. We can use bubble sort to sort the array and count the number of swaps.
Let's see how bubble sort works:
- Start from the first element, compare it with the second element, and swap them if the second element is smaller.
- Move to the second element, compare it with the third element, and swap them if the third element is smaller.
- Continue this process until the second-to-last element. At this point, the largest element is in the last position.
- Repeat the above process for the remaining elements, but exclude the last position.
In each iteration of the above process, we can count the number of swaps made. Therefore, the total number of swaps needed to sort the array can be obtained by summing up the number of swaps made in each iteration.
Implementation:
We can implement the above approach using a simple bubble sort algorithm. Here's the code:
- First, we read the input array and store it in a vector.
- We define a variable to keep track of the total number of swaps made and set it to 0.
- We run a loop from the first element to the second-to-last element.
- In each iteration of the above loop, we run another loop from the first element to the second-to-last element minus the current iteration index.
- In each iteration of the inner loop, we compare the current element with the next element and swap them if the next element is smaller.
- If a swap is made, we increment the total number of swaps made.
- Finally, we output the total number of swaps made.
Time Complexity:
The time complexity of bubble sort is O(n^2). Therefore, the overall time complexity of the solution is O(n^2).
Space Complexity:
We are using a vector to store the input array. Therefore, the space complexity of the solution is O(n).
Let's see the implementation of the solution.