根据以下要求写出java代码：The isIn method indicates whether the point at coordinates (x, y) (which are the arguments of the method) is currently inside the bubble or not. The edge of the bubble counts as being inside of the bubble. HINT: use Pythagoras's theorem to compute the distance from the center of the bubble to the po

int (x,y)，然后检查这个距离是否小于或等于圆的半径。

代码如下：

public class Bubble {
    private int x;
    private int y;
    private int radius;

    // constructor
    public Bubble(int x, int y, int radius) {
        this.x = x;
        this.y = y;
        this.radius = radius;
    }

    // check if point is inside the bubble
    public boolean isIn(int x, int y) {
        double distance = Math.sqrt(Math.pow(x - this.x, 2) + Math.pow(y - this.y, 2));
        return distance <= this.radius;
    }
}

在上面的代码中，我们定义了一个名为Bubble的类。该类包含x，y和radius属性，表示气泡的中心坐标和半径。我们还定义了一个构造函数，以便在创建类的实例时初始化这些属性。

isIn方法接受x和y作为参数，并使用勾股定理计算从气泡中心到点的距离。然后，我们检查距离是否小于或等于气泡的半径。如果是，则该点在气泡内部，返回true；否则，该点在气泡外部，返回false。

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根据以下要求写出代码：The isIn method indicates whether the point at coordinates (x, y) (which are the arguments of the method) is currently inside the bubble or not. The edge of the bubble counts as being inside of the bubble. HINT: use Pythagoras's theorem to compute the distance from the center of the bubble to the point (x, y). The draw method uses the graphics object g to draw the bubble. HINT: remember that the color of the graphics object g is changed in the draw method of the superclass of Bubble. Also add a testBubble method to test all your methods (including inherited methods, but excluding the isVisible method, which I provide, and excluding the draw method since it requires as argument a graphics object g that you

没有提供) by creating a Bubble object and calling its methods.

import math

class Bubble:
    def __init__(self, x, y, radius, color):
        self.x = x
        self.y = y
        self.radius = radius
        self.color = color
        
    def draw(self, g):
        g.setColor(self.color)
        g.fillOval(self.x - self.radius, self.y - self.radius, 2*self.radius, 2*self.radius)
        
    def isIn(self, x, y):
        distance = math.sqrt((x - self.x)**2 + (y - self.y)**2)
        return distance <= self.radius
        
    def testBubble(self):
        #creating a Bubble object
        bubble = Bubble(50, 50, 30, "blue")
        
        #testing inherited method
        print(bubble.isVisible())
        
        #testing own method
        print(bubble.isIn(60, 60))
        
        #testing own method
        print(bubble.isIn(90, 90))
        
        #testing own method
        print(bubble.isIn(80, 50))
        
        #testing draw method (requires graphics object g, which is not provided)
        #g = graphics object
        #bubble.draw(g)
        
bubble = Bubble(50, 50, 30, "blue")
bubble.testBubble()

The x and y instance variables indicate the position of the center of the shape, and the color instance variable indicates the color of the shape. The color of the shape is computed randomly in the constructor of the shape class and never changes after that, like this: color = new Color((float)Math.random(), (float)Math.random(), (float)Math.random()); The isVisible method is abstract, and indicates whether the shape is currently visible or not inside a window of width w and of height h. The isIn method is abstract, and indicates whether the point at coordinates (x, y) is currently inside the shape or not. The draw method simply changes the color of the graphics object g to be the correct color for the shape. Also add to your program a Start class to test your Shape class.帮我写出以上Java代码

以下是一个可能的实现：

import java.awt.Color;
import java.awt.Graphics;

public abstract class Shape {
    protected int x, y;
    protected Color color;

    public Shape(int x, int y) {
        this.x = x;
        this.y = y;
        color = new Color((float)Math.random(), (float)Math.random(), (float)Math.random());
    }

    public abstract boolean isVisible(int w, int h);

    public abstract boolean isIn(int x, int y);

    public void draw(Graphics g) {
        g.setColor(color);
    }
}

public class Start {
    public static void main(String[] args) {
        Shape shape = new Circle(50, 50, 20);
        System.out.println("Is shape visible? " + shape.isVisible(100, 100));
        System.out.println("Is (60, 60) inside shape? " + shape.isIn(60, 60));
    }
}

注意，上面的代码中 Shape 是一个抽象类，不能被直接实例化。你需要创建特定的子类来实现 isVisible 和 isIn 方法。例如，下面是一个可能的 Circle 类的实现：

public class Circle extends Shape {
    private int radius;

    public Circle(int x, int y, int radius) {
        super(x, y);
        this.radius = radius;
    }

    @Override
    public boolean isVisible(int w, int h) {
        return x - radius > 0 && x + radius < w && y - radius > 0 && y + radius < h;
    }

    @Override
    public boolean isIn(int x, int y) {
        return Math.sqrt((x - this.x) * (x - this.x) + (y - this.y) * (y - this.y)) <= radius;
    }

    public void draw(Graphics g) {
        super.draw(g);
        g.fillOval(x - radius, y - radius, 2 * radius, 2 * radius);
    }
}

注意，上面的 Circle 类重写了 Shape 类的 draw 方法，实现了在图形上绘制圆的功能。你可以创建其他的子类来实现不同的形状。