修正下列代码merged_report = {} a = 0 b = 0 c = 0 d = 0 for i in range(len(report)): for key in report[0].keys(): a += report[i][key]['precision'] b += report[i][key]['recall'] c += report[i][key]['f1-score'] d += report[i][key]['support'] merged_report[key] = { 'precision': a / n, 'recall': b / n, 'f1-score': c / n, 'support': d }
时间: 2024-03-04 17:48:04 浏览: 19
修正后的代码如下所示:
```
merged_report = {}
precision_sum = 0
recall_sum = 0
f1_score_sum = 0
support_sum = 0
n = len(report)
for key in report[0].keys():
for i in range(n):
precision_sum += report[i][key]['precision']
recall_sum += report[i][key]['recall']
f1_score_sum += report[i][key]['f1-score']
support_sum += report[i][key]['support']
merged_report[key] = {
'precision': precision_sum / n,
'recall': recall_sum / n,
'f1-score': f1_score_sum / n,
'support': support_sum
}
precision_sum = 0
recall_sum = 0
f1_score_sum = 0
support_sum = 0
```
修改的内容包括:
1. 将变量a、b、c、d改为precision_sum、recall_sum、f1_score_sum、support_sum,更加易读。
2. 将两个for循环的嵌套顺序进行交换,先遍历keys,再遍历report,保证每个key都能处理完毕。
3. 在第二个for循环中,将a、b、c、d的计算放入循环内部,并且每次计算后都将其重置为0,以避免累加计算的错误。
4. 将n的计算放到代码最开始部分,避免重复计算。