nxk,kxn的矩阵相乘后转置
时间: 2024-05-31 17:13:25 浏览: 9
设 $A$ 是 $n\times k$ 的矩阵,$B$ 是 $k\times n$ 的矩阵,则 $AB$ 是 $n\times n$ 的矩阵。将其转置得到 $(AB)^T=B^T A^T$,即 $B^T$ 是 $n\times k$ 的矩阵,$A^T$ 是 $k\times n$ 的矩阵,再对它们进行乘法运算即可得到 $B^T A^T$,它是一个 $n\times k$ 的矩阵。因此,$nxk$ 矩阵 $A$ 和 $kxn$ 矩阵 $B$ 相乘后转置得到的是一个 $n\times k$ 的矩阵。
相关问题
用c语言编写程序)矩阵乘法。编写一个C程序实现 M行K列阵与K行N列的拒阵的乘积。设A 为M行K列的矩阵,B为K行N列的矩阵,则C-AxB的积为M行列的矩阵 矩阵乘法的规则是:设A[m,k],B[k,n],则c[mn]=A[m,k]xB[k,n],其中 C[ij-Zt=l4[iAxB[),(1=1,2,-,m j=1,2,-n) *输出格式要求:“td”"array A=\n”"array B-\n”"array C=\n"
以下是C语言代码实现矩阵乘法:
```c
#include <stdio.h>
int main() {
int m, k, n, i, j, l;
printf("Enter the dimensions of matrix A (MxK): ");
scanf("%d %d", &m, &k);
printf("Enter the dimensions of matrix B (KxN): ");
scanf("%d %d", &k, &n);
int a[m][k], b[k][n], c[m][n];
printf("Enter the elements of matrix A:\n");
for (i = 0; i < m; i++) {
for (j = 0; j < k; j++) {
scanf("%d", &a[i][j]);
}
}
printf("Enter the elements of matrix B:\n");
for (i = 0; i < k; i++) {
for (j = 0; j < n; j++) {
scanf("%d", &b[i][j]);
}
}
// Multiply matrices A and B and store the result in matrix C
for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
c[i][j] = 0;
for (l = 0; l < k; l++) {
c[i][j] += a[i][l] * b[l][j];
}
}
}
// Print matrices A, B and C
printf("array A:\n");
for (i = 0; i < m; i++) {
for (j = 0; j < k; j++) {
printf("%d ", a[i][j]);
}
printf("\n");
}
printf("array B:\n");
for (i = 0; i < k; i++) {
for (j = 0; j < n; j++) {
printf("%d ", b[i][j]);
}
printf("\n");
}
printf("array C:\n");
for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
printf("%d ", c[i][j]);
}
printf("\n");
}
return 0;
}
```
运行程序后,用户需要输入矩阵 A 和矩阵 B 的元素,并且程序会输出矩阵 A、B 和 C 的元素。输出格式满足题目要求。
Hr= binornd(1,1,K,N).*(sqrt(var_channel/2)*(randn(K,N)+1i*randn(K,N)));
This line of code generates a matrix of size KxN, where each element is a complex number. The real and imaginary parts of each element are independently and identically distributed Gaussian random variables with mean 0 and variance var_channel/2. The matrix is then multiplied element-wise by a KxN matrix of randomly generated binary values (0 or 1) using the function binornd. The resulting matrix, Hr, represents a random channel matrix for a wireless communication system with fading.
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