沙发床SleepSofa,是一个沙发Sofa,也是一张床Bed,即类SleepSofa继承类Sofa和类Bed,关系如图所示。床和沙发都是家具的一种,因此定义公共基类家具类furniture,含数据成员weight,带参构造函数及成员函数 Setweight(),Showeight();沙发类Sofa与床类Bed分别继承自furniture,沙发床类SleepSofa继承类Sofa和类Bed。 将furniture定义为虚基类,在主函数中定义SleepSofa的对象,测试类的功能
时间: 2023-07-10 16:10:54 浏览: 29
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首先,让我们定义一个家具类furniture作为虚基类:
```cpp
class furniture {
protected:
double weight;
public:
furniture(double w) : weight(w) {}
virtual void Setweight(double w) { weight = w; }
virtual void Showweight() const { cout << "The weight is " << weight << " kg." << endl; }
};
```
然后,我们定义一个沙发类Sofa和一个床类Bed,它们都继承自furniture类:
```cpp
class Sofa : virtual public furniture {
public:
Sofa(double w) : furniture(w) {}
void Sit() const { cout << "You can sit on the sofa." << endl; }
};
class Bed : virtual public furniture {
public:
Bed(double w) : furniture(w) {}
void Sleep() const { cout << "You can sleep on the bed." << endl; }
};
```
最后,我们定义一个沙发床类SleepSofa,它继承自Sofa和Bed类:
```cpp
class SleepSofa : public Sofa, public Bed {
public:
SleepSofa(double w) : furniture(w), Sofa(w), Bed(w) {}
void FoldOut() const { cout << "The sofa can be folded out to a bed." << endl; }
};
```
现在,我们可以在主函数中创建SleepSofa的对象,并测试它的功能:
```cpp
int main() {
SleepSofa ss(50);
ss.Sit();
ss.Sleep();
ss.FoldOut();
ss.Setweight(60);
ss.Showweight();
return 0;
}
```
输出结果为:
```
You can sit on the sofa.
You can sleep on the bed.
The sofa can be folded out to a bed.
The weight is 60 kg.
```
这说明我们定义的面向对象类的继承关系和成员函数都是正确的。