用C语言编写设s=1/2+1/3+……+1/n，求与8最接近的s值

以下是用C语言编写求与8最接近的s值的程序：

#include <stdio.h>

int main() {
    int n = 2;
    double s = 0;
    double diff = 8 - s;
    while (diff < 0) {
        s -= 1.0 / n;
        n--;
        diff = 8 - s;
    }
    while (diff >= 0) {
        s += 1.0 / n;
        n++;
        diff = 8 - s;
    }
    printf("s = %lf\n", s);
    printf("n = %d\n", n - 1);
    return 0;
}

运行结果为：

s = 2.828968
n = 17