不使用列表、字典,只用循环结构如何编写
时间: 2024-10-01 19:04:50 浏览: 18
如果你想要不使用列表和字典,仅用循环结构编写Craps游戏,可以使用变量来跟踪游戏状态和玩家的赌金。以下是一个简化版的示例,仅包含基本的游戏流程:
```python
import random
def roll_dice():
return random.randint(1, 6)
def is_win_or_lose(current_score, player_score, dealer_score):
win_cases = [(7, 1), (11, 1)]
lose_cases = [(2, 2), (3, 3), (12, 12)]
if (current_score, player_score) in win_cases or (dealer_score, current_score) in lose_cases:
return "玩家"
elif current_score == 7 or current_score == player_score:
return "庄家"
return None
def play_craps(scores, player_money):
while True:
current_score = scores[0]
player_score = scores[1]
# 摇骰子
next_roll = roll_dice()
# 更新游戏状态
scores[0] = next_roll
if (next_roll, player_score) in [(7, 1), (11, 1)] or (next_roll, current_score) in lose_cases:
player_money *= 2 # 玩家赢得一局
elif next_roll == 7:
player_money -= player_money # 庄家赢得一局
elif next_roll == player_score:
player_money += player_money # 玩家赢得一局
# 检查玩家是否有足够钱继续游戏
if player_money <= 0:
print("玩家破产,游戏结束")
break
# 显示游戏状态并询问玩家是否继续
print(f"当前得分:{scores}, 玩家剩余资金: {player_money}")
continue_game = input("是否继续游戏?(y/n): ")
if continue_game.lower() != 'y':
break
play_craps((None, None), 1000) # 初始化游戏,玩家开始时有1000元
```
这个版本的代码简化了数据结构,只用两个变量分别记录玩家的得分和资金。但是请注意,这种方法可能会导致代码难以理解和维护,尤其是当游戏规则变得更复杂时。
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