stm32f103c8t6驱动电机代码
时间: 2023-09-23 22:12:05 浏览: 159
STM32F103C8T6_ULN2003.rar
以下是使用STM32F103C8T6驱动直流电机的示例代码:
```c
#include "stm32f10x.h"
#define MOTOR_PIN GPIO_Pin_0
#define MOTOR_PORT GPIOA
void PWM_Init(void)
{
GPIO_InitTypeDef GPIO_InitStructure;
TIM_TimeBaseInitTypeDef TIM_TimeBaseStructure;
TIM_OCInitTypeDef TIM_OCInitStructure;
// 使能定时器时钟
RCC_APB1PeriphClockCmd(RCC_APB1Periph_TIM3, ENABLE);
// 使能GPIO时钟
RCC_APB2PeriphClockCmd(RCC_APB2Periph_GPIOA, ENABLE);
// 配置GPIO引脚
GPIO_InitStructure.GPIO_Pin = MOTOR_PIN;
GPIO_InitStructure.GPIO_Mode = GPIO_Mode_AF_PP;
GPIO_InitStructure.GPIO_Speed = GPIO_Speed_50MHz;
GPIO_Init(MOTOR_PORT, &GPIO_InitStructure);
// 配置定时器
TIM_TimeBaseStructure.TIM_Prescaler = 72 - 1; // 时钟预分频
TIM_TimeBaseStructure.TIM_Period = 5000 - 1; // 计数器周期
TIM_TimeBaseStructure.TIM_ClockDivision = TIM_CKD_DIV1;
TIM_TimeBaseStructure.TIM_CounterMode = TIM_CounterMode_Up;
TIM_TimeBaseInit(TIM3, &TIM_TimeBaseStructure);
// 配置PWM输出
TIM_OCInitStructure.TIM_OCMode = TIM_OCMode_PWM1;
TIM_OCInitStructure.TIM_OutputState = TIM_OutputState_Enable;
TIM_OCInitStructure.TIM_Pulse = 0; // 占空比
TIM_OCInitStructure.TIM_OCPolarity = TIM_OCPolarity_High;
TIM_OC3Init(TIM3, &TIM_OCInitStructure);
// 使能定时器
TIM_Cmd(TIM3, ENABLE);
// 使能PWM输出
TIM_CtrlPWMOutputs(TIM3, ENABLE);
}
void Motor_Run(uint16_t duty_cycle)
{
TIM_OCInitTypeDef TIM_OCInitStructure;
TIM_OCInitStructure.TIM_OCMode = TIM_OCMode_PWM1;
TIM_OCInitStructure.TIM_OutputState = TIM_OutputState_Enable;
TIM_OCInitStructure.TIM_Pulse = duty_cycle;
TIM_OCInitStructure.TIM_OCPolarity = TIM_OCPolarity_High;
TIM_OC3Init(TIM3, &TIM_OCInitStructure);
}
int main(void)
{
PWM_Init();
while(1)
{
Motor_Run(2500); // 占空比50%
Delay(1000);
Motor_Run(5000); // 占空比100%
Delay(1000);
Motor_Run(0); // 停止
Delay(1000);
}
}
```
注意:
1. 代码中使用了STM32F10x标准外设库,需要在工程中添加相应的库文件及头文件。
2. 代码中使用TIM3_CH3(PA6)输出PWM信号,需要连接一个N沟道MOS管,将MOS管的源极接地,负载接在MOS管的漏极上。
3. 占空比的计算公式:duty_cycle = (TIM_Period + 1) * (desired_duty_cycle / 100) - 1,其中TIM_Period为计数器周期,desired_duty_cycle为期望的占空比。例如,在本例中,计数器周期为5000,如果期望占空比为50%,则duty_cycle = (5000 + 1) * (50 / 100) - 1 = 2500。
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