let a=[{name:1,age:2}{name:2,age:3}] let b =[{msg:3,gge:4}{list:4,arr:5}] 输出 let c=[{name:1,age:2,msg:3,gge:4,list:4,arr:5}{name:2,age:3,msg:3,gge:4,list:4,arr:5}]

可以使用循环遍历数组 a 和 b，并将每个对象的属性添加到一个新的对象中，最后将新的对象添加到数组 c 中，具体实现如下：

let a = [{name:1,age:2}, {name:2,age:3}];
let b = [{msg:3,gge:4}, {list:4,arr:5}];
let c = [];

for(let i = 0; i < a.length; i++) {
  let obj = {};
  let keys = Object.keys(a[i]);
  for(let j = 0; j < keys.length; j++) {
    let key = keys[j];
    let value = a[i][key];
    obj[key] = value;
  }
  keys = Object.keys(b[0]);
  for(let j = 0; j < keys.length; j++) {
    let key = keys[j];
    let value = b[0][key];
    obj[key] = value;
  }
  keys = Object.keys(b[1]);
  for(let j = 0; j < keys.length; j++) {
    let key = keys[j];
    let value = b[1][key];
    obj[key] = value;
  }
  c.push(obj);
}

console.log(c);

输出结果为：

[
  {name: 1, age: 2, msg: 3, gge: 4, list: 4, arr: 5},
  {name: 2, age: 3, msg: 3, gge: 4, list: 4, arr: 5}
]

注意，这里假设数组 b 中有且仅有两个对象，如果有更多对象，就需要增加循环次数。