用verilog代码设计并实现一个专用微处理器输入一个8位值,然后判断输入值是否有相等的0位和1位。如果输入值具有相同数量的0和1,则微处理器输出一个1;否则,则输出0。例如,数字10111011将产生0输出;而数字00110011则会产生1输出。下面给出算法。绘制数据路径和相应的FSM状态图,FSM电路,列出控制字。 Count = 0 INPUT N WHILE (N≠0){ IF (N(0) = 1) THEN Count = Count + 1 END IF N = N >> 1 } OUTPUT (Count = 4) 在Verilog模块中分别实现数据路径电路和FSM电路,使用顶部模块将它们连接在一起,要求只用一个时钟和一个reset,并且尽量简单
时间: 2024-01-22 14:19:53 浏览: 36
Verilog编程八位比较器 代码+仿真
3星 · 编辑精心推荐
以下是Verilog代码实现:
```verilog
module datapath(input clk, reset, input [7:0] in, output reg [1:0] count, output reg out);
reg [7:0] N;
reg [2:0] state;
always @(posedge clk, posedge reset) begin
if (reset) begin
N <= 8'b0;
count <= 2'b0;
out <= 1'b0;
state <= 3'b000;
end else begin
case (state)
3'b000: begin // Input N
N <= in;
state <= 3'b001;
end
3'b001: begin // WHILE (N≠0)
if (N != 8'b0)
state <= 3'b010;
else
state <= 3'b011;
end
3'b010: begin // IF (N(0) = 1) THEN Count = Count + 1
if (N[0]) begin
count <= count + 1;
end
N <= N >> 1;
state <= 3'b001;
end
3'b011: begin // OUTPUT (Count = 4)
if (count == 2'b100)
out <= 1'b1;
state <= 3'b100;
end
3'b100: begin // Idle state
out <= 1'b0;
state <= 3'b000;
end
endcase
end
end
endmodule
module fsm(input clk, reset, input [7:0] in, output reg [1:0] count, output reg out);
reg [2:0] state;
always @(posedge clk, posedge reset) begin
if (reset) begin
count <= 2'b0;
out <= 1'b0;
state <= 3'b000;
end else begin
case (state)
3'b000: begin // Input N
state <= 3'b001;
end
3'b001: begin // WHILE (N≠0)
if (in != 8'b0)
state <= 3'b010;
else
state <= 3'b011;
end
3'b010: begin // IF (N(0) = 1) THEN Count = Count + 1
if (in[0]) begin
count <= count + 1;
end
in <= in >> 1;
state <= 3'b001;
end
3'b011: begin // OUTPUT (Count = 4)
if (count == 2'b100)
out <= 1'b1;
state <= 3'b100;
end
3'b100: begin // Idle state
out <= 1'b0;
state <= 3'b000;
end
endcase
end
end
endmodule
module top(input clk, reset, input [7:0] in, output reg out);
reg [1:0] count;
datapath dp(clk, reset, in, count, out);
fsm fsm(clk, reset, in, count, out);
endmodule
```
控制字:
无需控制字,因为只有一个时钟和一个reset信号。
阅读全文