data_root = os.path.abspath(os.path.join(os.getcwd(), "../..")) # get data root path image_path = os.path.join(data_root, "data")
时间: 2024-04-25 14:22:26 浏览: 20
这段代码的作用是获取数据的根路径,并拼接出图像数据的路径。首先,`os.getcwd()` 返回当前工作目录的路径。然后,`os.path.join()` 将当前工作目录路径与 "../.." 拼接起来,得到数据根路径。最后,`os.path.join()` 再将数据根路径与 "data" 拼接起来,得到图像数据的路径。
相关问题
data_root = os.path.abspath(os.path.join(os.getcwd(), "../.."))
This code snippet creates a variable called `data_root` that stores the absolute path of the parent directory of the current working directory.
Here's how it works:
- `os.getcwd()` returns the current working directory as a string.
- `os.path.join()` joins the current working directory with the relative path `"../.."` which represents the parent directory of the current directory.
- `os.path.abspath()` returns the absolute path of the joined path. This ensures that the path is in a standardized format with all symbolic links resolved and any relative paths converted to absolute paths.
Overall, this code is useful for navigating to a specific directory relative to the current working directory, regardless of where the code is run from.
data_root = os.path.abspath(os.path.join(os.getcwd(), "../.."))改成当前路径
要将data_root修改为当前路径,可以使用以下代码:
```python
import os
data_root = os.getcwd()
```
这将使用`os.getcwd()`函数获取当前工作目录的路径,并将其赋值给`data_root`变量。这样,`data_root`就代表了当前路径。