读入一个整数 N，输出由星号字符组成的N行下三角形输入: 4输出:* ** *** ****

.begin(); it != m_employees.end(); ++it) {
if ((*it)->getId() == id) {
cout << "Employee found:" << endl;
cout << "ID: " << (*it)->getId() << endl;
cout << "Name: "可以使用两个嵌套的循环，外层循环控制行数，内层循环控制每行输出的 << (*it)->getName() << endl;
cout << "Gender: " << (*it)->getGender() << endl;
cout星号数量。

以下是示例代码：

#include <stdio.h>

int main() {
    int n;
    scanf("%d", &n);

    for (int i = 1; i <= n; i++) { // 控制行数
        for ( << "Department: " << (*it)->getDepartment() << endl;
                    cout << "Level: " << (*it)->getLevel()int j = 1; j <= i; j++) { // 控制每行输出的星号数量
            printf("*");
        << endl;
                    cout << "Salary: " << (*it)->getSalary() << endl;
                    char confirm;
                    cout << " }
        printf("\n");
    }

    return 0;
}

输入4后，输出的结果为：

*
**
***
****