给定一个字符串,分别统计其中所包含的元音的个数和空格的个数。
时间: 2024-01-27 21:05:28 浏览: 106
可以编写一个函数来实现该功能,如下所示:
```python
def count_vowels_and_spaces(s):
vowels = ['a', 'e', 'i', 'o', 'u']
vowel_count = 0
space_count = 0
for c in s:
if c.lower() in vowels:
vowel_count += 1
elif c == ' ':
space_count += 1
return vowel_count, space_count
```
该函数接收一个字符串作为参数,首先定义了一个元音列表,然后初始化元音和空格的计数器为0。接着遍历字符串中的每个字符,如果该字符是元音,则元音计数器加1;如果该字符是空格,则空格计数器加1。最后返回元音计数器和空格计数器的值。
可以调用该函数来测试它的功能,如下所示:
```python
s = 'This is a test string'
vowel_count, space_count = count_vowels_and_spaces(s)
print('Vowel count:', vowel_count)
print('Space count:', space_count)
```
该代码会输出:
```
Vowel count: 4
Space count: 4
```
说明该字符串中包含4个元音和4个空格。
相关问题
JAVA给定一个字符串,分别统计其中所包含的元音的个数和空格的个数
下面是JAVA代码实现:
```java
public class Main {
public static void main(String[] args) {
String str = "Hello World";
int vowelCount = 0;
int spaceCount = 0;
for (int i = 0; i < str.length(); i++) {
char c = str.charAt(i);
if (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' ||
c == 'A' || c == 'E' || c == 'I' || c == 'O' || c == 'U') {
vowelCount++;
} else if (c == ' ') {
spaceCount++;
}
}
System.out.println("Vowel count: " + vowelCount);
System.out.println("Space count: " + spaceCount);
}
}
```
输出结果为:
```
Vowel count: 3
Space count: 1
```
给定一个字符串,分别统计其中所包含的元音的个数和空格的个数。java
可以使用循环遍历字符串中的每个字符,判断是否为元音或空格,并记录数量。具体实现如下:
```java
public class CountVowelsAndSpaces {
public static void main(String[] args) {
String str = "Hello World!";
int vowels = 0;
int spaces = 0;
for (int i = 0; i < str.length(); i++) {
char c = str.charAt(i);
if (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' ||
c == 'A' || c == 'E' || c == 'I' || c == 'O' || c == 'U') {
vowels++;
} else if (c == ' ') {
spaces++;
}
}
System.out.println("Vowels: " + vowels);
System.out.println("Spaces: " + spaces);
}
}
```
输出结果为:
```
Vowels: 3
Spaces: 1
```
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