用c++帮我写a = input()b = input()c = input()result = a.replace(b, c)print(result)

当然可以，以下是代码：

#include <stdio.h>
#include <string.h>

int main() {
char a[100], b[100], c[100], result[100];
printf("请输入a：");
scanf("%s", a);
printf("请输入b：");
scanf("%s", b);
printf("请输入c：");
scanf("%s", c);
strcpy(result, a);
char *p = strstr(result, b);
if (p != NULL) {
int len1 = strlen(a);
int len2 = strlen(b);
int len3 = strlen(c);
int len4 = strlen(p);
memmove(p + len3, p + len2, len4 - len2 + 1);
memcpy(p, c, len3);
}
printf("替换后的结果为：%s\n", result);
return 0;
}

相关问题

用c++解决下述问题：描述 Given a string S, print the results of the operations. Here are the operations: Insert x i: Insert the character x to the position i; Erase x: Delete all characters x in S; Replace x y: Replace all characters x by y S; Size: Print the size of S; Reverse: Print the reverse of S; Don't change S in this operation; Sub i j: Print the substring of S from position i to j; Find str: Print the starting postion of the "first" str in S; If str is not a substring of S, print -1. 输入 The first line of each test case contains a string S. Then 5 lines follow. The first line includes a character x and an integer i, meaning "Insert x i"; The second line is a character x, meaning "Erase x"; The third line are two characters x and y, meaning "Replace x y"; The fourth line are two integers i and j, meaning "Sub i j"; The last line is a string str, meaning "Find str". All the input characters are English uppercase or lowercase letters. The length of the string will not exceed 100. Inputs will be terminated at the end of the file. 输出 For each test case, you must print "Case i:" in the first line. Then for each operation, print its result in one line. There will be a blank line after each test case.

很高兴为您解答这道题目，以下是C++代码实现：

#include <iostream>
#include <string>
#include <algorithm>

using namespace std;

int main() {
    string S;
    int case_num = 1;
    while (getline(cin, S)) {
        cout << "Case " << case_num << ":" << endl;
        case_num++;
        
        string x, y, str;
        int i, j;
        
        // Insert x i
        cin >> x >> i;
        S.insert(i, x);
        cout << S << endl;
        
        // Erase x
        cin >> x;
        S.erase(remove(S.begin(), S.end(), x[0]), S.end());
        cout << S << endl;
        
        // Replace x y
        cin >> x >> y;
        replace(S.begin(), S.end(), x[0], y[0]);
        cout << S << endl;
        
        // Size
        cout << S.size() << endl;
        
        // Reverse
        reverse(S.begin(), S.end());
        cout << S << endl;
        reverse(S.begin(), S.end());
        
        // Sub i j
        cin >> i >> j;
        cout << S.substr(i, j-i+1) << endl;
        
        // Find str
        cin >> str;
        int pos = S.find(str);
        if (pos == string::npos) {
            cout << -1 << endl;
        } else {
            cout << pos << endl;
        }
        
        // Blank line
        cout << endl;
        cin.ignore();
    }
    return 0;
}

该代码使用了字符串的 STL 库，包括 `insert`，`erase`，`replace`，`size`，`reverse`，`substr` 和 `find` 函数。其中，`erase` 函数使用了 `remove` 函数来删除所有字符 x。

程序的输入方式是使用 `getline` 函数读取一行字符串，然后使用 `cin` 读取操作所需的参数。最后，使用 `cout` 输出结果，并在每个测试用例之间输出一个空行。

希望能够帮到您！

Traceback (most recent call last): File "C:/Users/admin/Desktop/QA相关/Python_QA_压力测试脚本/源码/gao10c.py", line 25, in <module> result_str = lib.parseLog(input_data_hex.encode('utf-8'), 474, output_data, ctypes.byref(output_len)) ctypes.ArgumentError: argument 1: <class 'TypeError'>: expected LP_c_char_p instance instead of bytes

这个错误是因为`input_data_hex.encode('utf-8')`返回的是`bytes`类型，而C++函数的参数类型是`const char*`。在`ctypes`中，`bytes`类型需要使用`ctypes.c_char_p`类型来表示。

所以您需要将`input_data_hex.encode('utf-8')`改为`ctypes.c_char_p(input_data_hex.encode('utf-8'))`，具体代码如下：

C++代码：

#include <iostream>
#include <string>

using namespace std;

extern "C" __declspec(dllexport) int parseLog(const char* input_data, int input_len, char* output_data, int* output_len) {
    string input(input_data, input_len);
    cout << "Input data: " << input << endl;
    // Do something with the input data
    string output = "Output data";
    cout << "Output data: " << output << endl;
    strcpy_s(output_data, output.length() + 1, output.c_str());
    *output_len = output.length();
    return 0;
}

Python代码：

import ctypes

# 加载DLL文件
lib = ctypes.cdll.LoadLibrary("your_lib.dll")

# 设置函数参数类型和返回值类型
lib.parseLog.argtypes = [ctypes.c_char_p, ctypes.c_int, ctypes.c_char_p, ctypes.POINTER(ctypes.c_int)]
lib.parseLog.restype = ctypes.c_int

# 调用函数
input_data_hex = "9A FF 01 01 02 4B 05 28 F3 19 01 01 02 29 00 00 02"
input_data = input_data_hex.replace(" ", "")
output_data = ctypes.create_string_buffer(1024)
output_len = ctypes.c_int(0)
result = lib.parseLog(ctypes.c_char_p(input_data.encode('utf-8')), len(input_data), output_data, ctypes.byref(output_len))
if result == 0:
    print("Output data length: ", output_len.value)
    print("Output data: ", output_data.value.decode('utf-8'))
else:
    print("Failed to parse log!")

在Python代码中，我们将`input_data_hex.encode('utf-8')`改为了`ctypes.c_char_p(input_data_hex.encode('utf-8'))`，并且添加了`len(input_data)`参数来表示输入数据的长度。我们还使用`ctypes.create_string_buffer`函数创建了一个缓冲区来存储输出数据，使用`ctypes.byref`传递了输出数据长度的指针。最后，我们使用`output_data.value.decode('utf-8')`来获取输出数据的字符串表示。