c++实现消消乐小程序对应代码
时间: 2023-10-10 13:13:22 浏览: 153
消消乐游戏c语言代码
消消乐小程序的实现方式有很多种,以下是一种简单的C++实现,仅供参考。这个实现方式使用了二维数组来存储游戏棋盘,使用递归方式实现了消除方块的逻辑。
```c++
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;
const int ROWS = 8;
const int COLS = 8;
const char BLOCKS[] = {'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L'};
const int BLOCK_NUM = 12;
char board[ROWS][COLS];
void initBoard() {
srand(time(NULL));
for (int i = 0; i < ROWS; i++) {
for (int j = 0; j < COLS; j++) {
board[i][j] = BLOCKS[rand() % BLOCK_NUM];
}
}
}
bool canEliminate(int x1, int y1, int x2, int y2) {
if (board[x1][y1] != board[x2][y2]) {
return false;
}
if (x1 == x2 && y1 == y2) {
return false;
}
if (x1 == x2) {
int minY = min(y1, y2);
int maxY = max(y1, y2);
for (int i = minY + 1; i < maxY; i++) {
if (board[x1][i] != '*') {
return false;
}
}
return true;
}
if (y1 == y2) {
int minX = min(x1, x2);
int maxX = max(x1, x2);
for (int i = minX + 1; i < maxX; i++) {
if (board[i][y1] != '*') {
return false;
}
}
return true;
}
return false;
}
bool canEliminate(int x1, int y1, int x2, int y2, int x3, int y3) {
return canEliminate(x1, y1, x2, y2) && canEliminate(x2, y2, x3, y3) && canEliminate(x1, y1, x3, y3);
}
bool eliminate(int x1, int y1, int x2, int y2) {
if (!canEliminate(x1, y1, x2, y2)) {
return false;
}
board[x1][y1] = board[x2][y2] = '*';
for (int i = 0; i < ROWS; i++) {
for (int j = 0; j < COLS; j++) {
if (board[i][j] == '*') {
continue;
}
if (i > 0 && board[i - 1][j] == '*' && canEliminate(i, j, i - 1, j)) {
eliminate(i, j, i - 1, j);
return true;
}
if (i < ROWS - 1 && board[i + 1][j] == '*' && canEliminate(i, j, i + 1, j)) {
eliminate(i, j, i + 1, j);
return true;
}
if (j > 0 && board[i][j - 1] == '*' && canEliminate(i, j, i, j - 1)) {
eliminate(i, j, i, j - 1);
return true;
}
if (j < COLS - 1 && board[i][j + 1] == '*' && canEliminate(i, j, i, j + 1)) {
eliminate(i, j, i, j + 1);
return true;
}
}
}
for (int i = 0; i < ROWS; i++) {
for (int j = 0; j < COLS; j++) {
if (board[i][j] == '*') {
int k = i;
while (k > 0) {
swap(board[k][j], board[k - 1][j]);
k--;
}
board[k][j] = BLOCKS[rand() % BLOCK_NUM];
}
}
}
return true;
}
bool canEliminate() {
for (int i = 0; i < ROWS; i++) {
for (int j = 0; j < COLS; j++) {
if (board[i][j] == '*') {
continue;
}
if (i > 0 && board[i - 1][j] == '*' && canEliminate(i, j, i - 1, j)) {
return true;
}
if (i < ROWS - 1 && board[i + 1][j] == '*' && canEliminate(i, j, i + 1, j)) {
return true;
}
if (j > 0 && board[i][j - 1] == '*' && canEliminate(i, j, i, j - 1)) {
return true;
}
if (j < COLS - 1 && board[i][j + 1] == '*' && canEliminate(i, j, i, j + 1)) {
return true;
}
}
}
return false;
}
void printBoard() {
for (int i = 0; i < ROWS; i++) {
for (int j = 0; j < COLS; j++) {
cout << board[i][j] << ' ';
}
cout << endl;
}
cout << endl;
}
int main() {
initBoard();
while (canEliminate()) {
printBoard();
int x1, y1, x2, y2;
cout << "Please input the position of two blocks to eliminate: ";
cin >> x1 >> y1 >> x2 >> y2;
if (eliminate(x1, y1, x2, y2)) {
cout << "Eliminated!" << endl;
} else {
cout << "Can't eliminate!" << endl;
}
}
cout << "Game over!" << endl;
return 0;
}
```
这个实现方式中使用了一个二维数组来存储游戏棋盘,使用随机数初始化了棋盘,并使用递归方式实现了消除方块的逻辑。可以通过调用initBoard()函数初始化棋盘,通过调用printBoard()函数打印棋盘,通过调用eliminate()函数消除两个方块,并通过调用canEliminate()函数判断是否还有可以消除的方块,从而实现整个消消乐小程序的功能。
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