#include <stdio.h> #include <stdlib.h> void main() short int i,j,sum; i=32767: j=1; sum=i+j; printf("sum=%d/n",sum); 1system("pause");}
时间: 2024-09-28 13:10:58 浏览: 49
这段代码是一个简单的C语言程序,它的功能是在控制台上计算并打印两个整数`i`和`j`相加的结果,并暂停一段时间让用户查看。以下是程序的逐行解析:
```c
#include <stdio.h> // 包含输入输出库,用于标准I/O函数
#include <stdlib.h> // 包含系统库,用于 pause 函数
void main() // 主函数
{
short int i, j, sum; // 定义三个整型变量,其中i和j为short类型,sum用于存储和
i = 32767; // 将i赋值为short类型的最大负整数,注意short通常范围是-32768到32767
j = 1; // 将j赋值为1
sum = i + j; // 计算i和j的和并将结果存入sum
printf("sum=%d\n", sum); // 输出结果到控制台,格式化字符串带有一个%d表示整数占位符
1("pause");} // 使用1作为暂停命令,实际上这是错误的,因为1不会暂停程序,这里只是为了展示语法错误
```
相关问题
将下列代码转为c语言module uart( input clk, input rst, input rx_data, output tx_data) reg [7:0]state; reg [3:0] num; reg [15:0] sum; reg [7:0] sum_1; reg [15:0] mem[0:9]; always@(posedge clk or negedge rst) begin if(!rst)begin data <= 0; num <= 0; mem[0:9] <= 0; sum <= 0; state <= 8'd0;end else begin case(state) 8'd0:if(data <= 0x54)begin sum <= data+sum; mem[0] <= data; num <= 1; state <= 8'd1; end else begin sum <= sum; state <= 8'd0; end 8'd1:if(num <= 9)begin sum <= data+sum; num <= num+1; state <= 8'd1; mem[num] <= data; end; else begin sum_1 <= (sum&0xff); num <= 0; state <= 8'd2; end 8'd2:if(sum_1 == mem[9]) tx_data <= mem[num]; state <= 8'd3; num <= num+1; end else begin tx_data <= 0; state <= 8'd0; mem [7:0] <= 16'd0; num <= 0; sum <= 0; sum_1 <= 0; end 8'd3:if(num <= 9)begin tx_data <= mem[num]; num <= num +1; state <= state+1; end else begin sum <= 0; sum_1 <= 0; state <= 8'd0; mem[7:0] <= 16'd0; end endcase end end endmodule
以下是将Verilog代码转换为C语言的代码:
```c
#include <stdio.h>
#include <stdlib.h>
#define rst_n 0
#define clk 1
#define rx_data 2
#define tx_data 3
unsigned char state = 0;
unsigned char num = 0;
unsigned short sum = 0;
unsigned char sum_1 = 0;
unsigned short mem[10];
void uart(unsigned char clk, unsigned char rst, unsigned char rx_data, unsigned char* tx_data) {
if (!rst) {
*tx_data = 0;
num = 0;
for (int i = 0; i < 10; i++) {
mem[i] = 0;
}
sum = 0;
sum_1 = 0;
state = 0;
} else {
unsigned char data = rx_data;
switch (state) {
case 0:
if (data <= 0x54) {
sum += data;
mem[0] = data;
num = 1;
state = 1;
} else {
sum = sum;
state = 0;
}
break;
case 1:
if (num <= 9) {
sum += data;
num++;
state = 1;
mem[num] = data;
} else {
sum_1 = sum & 0xFF;
num = 0;
state = 2;
}
break;
case 2:
if (sum_1 == mem[9]) {
*tx_data = mem[num];
num++;
state = 3;
} else {
*tx_data = 0;
state = 0;
for (int i = 0; i < 8; i++) {
mem[i] = 0;
}
num = 0;
sum = 0;
sum_1 = 0;
}
break;
case 3:
if (num <= 9) {
*tx_data = mem[num];
num++;
state++;
} else {
sum = 0;
sum_1 = 0;
state = 0;
for (int i = 0; i < 8; i++) {
mem[i] = 0;
}
}
break;
default:
break;
}
}
}
int main() {
unsigned char rx_data = 0x05;
unsigned char tx_data = 0;
uart(clk, rst_n, rx_data, &tx_data);
printf("%d\n", tx_data);
return 0;
}
```
注意,这里的代码只是对 Verilog 代码的简单翻译,没有进行代码优化和功能测试,还需要根据实际需求进行修改和完善。
vector<vector<AUDIO_DATA_TYPE>> allMixingSounds
在C语言中,没有直接的内置容器类型像C++中的`vector`。但是,我们可以使用指针和动态分配的内存来模拟二维数组。以下是使用C语言实现`vector<vector<AUDIO_DATA_TYPE>>`的示例代码:
```c
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
typedef short AUDIO_DATA_TYPE;
typedef struct {
AUDIO_DATA_TYPE* data;
size_t size;
} Vector;
typedef struct {
Vector* data;
size_t size;
} VectorVector;
void initVector(Vector* vec) {
vec->data = NULL;
vec->size = 0;
}
void pushBackVector(Vector* vec, AUDIO_DATA_TYPE value) {
vec->data = realloc(vec->data, (vec->size + 1) * sizeof(AUDIO_DATA_TYPE));
vec->data[vec->size] = value;
vec->size++;
}
void initVectorVector(VectorVector* vecVec) {
vecVec->data = NULL;
vecVec->size = 0;
}
void pushBackVectorVector(VectorVector* vecVec, Vector vec) {
vecVec->data = realloc(vecVec->data, (vecVec->size + 1) * sizeof(Vector));
vecVec->data[vecVec->size] = vec;
vecVec->size++;
}
void freeVector(Vector* vec) {
free(vec->data);
}
void freeVectorVector(VectorVector* vecVec) {
for (size_t i = 0; i < vecVec->size; i++) {
freeVector(&(vecVec->data[i]));
}
free(vecVec->data);
}
void MixSoundsBySimplyAdd(VectorVector allMixingSounds,
DWORD RawDataCnt,
Vector* __pRawDataBuffer)
{
typedef int WIDEN_TEMP_TYPE;
const WIDEN_TEMP_TYPE AUDIO_DATA_TYPE_MAX = SHRT_MAX;
const WIDEN_TEMP_TYPE AUDIO_DATA_TYPE_MIN = SHRT_MIN;
WIDEN_TEMP_TYPE Sum = 0;
for (int i = 0; i < RawDataCnt; ++i)
{
Sum = 0;
for (int wavNum = 0; wavNum < allMixingSounds.size; ++wavNum)
{
Sum += allMixingSounds.data[wavNum].data[i];
}
if (Sum > AUDIO_DATA_TYPE_MAX)
Sum = AUDIO_DATA_TYPE_MAX;
else if (Sum < AUDIO_DATA_TYPE_MIN)
Sum = AUDIO_DATA_TYPE_MIN;
pushBackVector(__pRawDataBuffer, AUDIO_DATA_TYPE(Sum));
}
}
int main() {
VectorVector allMixingSounds;
initVectorVector(&allMixingSounds);
// 添加数据到allMixingSounds
Vector vec1;
initVector(&vec1);
pushBackVector(&vec1, 1);
pushBackVector(&vec1, 2);
pushBackVector(&vec1, 3);
pushBackVectorVector(&allMixingSounds, vec1);
Vector vec2;
initVector(&vec2);
pushBackVector(&vec2, 4);
pushBackVector(&vec2, 5);
pushBackVector(&vec2, 6);
pushBackVectorVector(&allMixingSounds, vec2);
// 创建输出缓冲区
Vector rawDataBuffer;
initVector(&rawDataBuffer);
// 调用MixSoundsBySimplyAdd函数
MixSoundsBySimplyAdd(allMixingSounds, 3, &rawDataBuffer);
// 输出结果
for (int i = 0; i < rawDataBuffer.size; i++) {
printf("%d ", rawDataBuffer.data[i]);
}
printf("\n");
// 释放内存
freeVectorVector(&allMixingSounds);
freeVector(&rawDataBuffer);
return 0;
}
```
以上代码演示了如何使用指针和动态分配的内存来模拟`vector<vector<AUDIO_DATA_TYPE>>`。你可以根据自己的需求进行修改和调整。请注意,在使用完后,需要对动态分配的内存进行释放,以避免内存泄漏。
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