写一程序，完成求s=1+3+5+..+99+101

#include <stdio.h>

int main() {
    int s = 0;
    for (int i = 1; i <= 101; i += 2) {
        s += i;
    }
    printf("s = %d\n", s);
    return 0;
}

输出结果为：s = 2601