expire_seconds=$(date -d "$(chage -l <username> | grep "Account expires" | cut -d':' -f2)" +"%s")
时间: 2024-06-08 08:05:39 浏览: 5
这段代码是用来获取用户账户过期时间的,具体解释如下:
1. `chage -l <username>`:该命令用于列出指定用户的账户信息;
2. `grep "Account expires"`:该命令用于获取包含"Account expires"的那一行;
3. `cut -d':' -f2`:该命令用于获取以冒号分隔的第二个字段,即账户过期时间;
4. `date -d "$(chage -l <username> | grep "Account expires" | cut -d':' -f2)" +"%s"`:该命令用于将账户过期时间转化为时间戳。
综上,这段代码的作用是获取指定用户账户的过期时间,并将其转化为时间戳。
相关问题
#!/bin/bash users=$(cut -d: -f1 /etc/passwd) for user in $users do if [[ $(getent passwd $user | cut -d: -f3) -ge 1000 ]] then if [[ $(chage -l $user | grep "Password expires" | grep "密码过期时间" | cut -d: -f2 | tr -d ' ') == "never" || $(chage -l $user | grep "Password expires" | grep "密码过期时间" | cut -d: -f2 | tr -d ' ') == "从不" ]] then echo "$user: Password never expires" else expire_date=$(date -d "$(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" +%s) current_date=$(date +%s) if [[ $expire_date -lt $current_date ]] then echo "$(hostname -I | awk '{print $1}'), $user: Password has expired" else echo "$user: Password will expire on $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" fi fi else account_status=$(passwd -S $user | awk '{print $2}') if [[ "$account_status" == "L" ]]; then echo "$(hostname -I | awk '{print $1}'), User $user: account locked!" fi fi done帮我把这段代码的第一个if去掉
好的,这是去掉第一个if之后的代码:
```bash
#!/bin/bash
users=$(cut -d: -f1 /etc/passwd)
for user in $users
do
if [[ $(chage -l $user | grep "Password expires" | grep "密码过期时间" | cut -d: -f2 | tr -d ' ') == "never" || $(chage -l $user | grep "Password expires" | grep "密码过期时间" | cut -d: -f2 | tr -d ' ') == "从不" ]]
then
echo "$user: Password never expires"
else
expire_date=$(date -d "$(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" +%s)
current_date=$(date +%s)
if [[ $expire_date -lt $current_date ]]
then
echo "$(hostname -I | awk '{print $1}'), $user: Password has expired"
else
echo "$user: Password will expire on $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')"
fi
fi
account_status=$(passwd -S $user | awk '{print $2}')
if [[ "$account_status" == "L" ]]; then
echo "$(hostname -I | awk '{print $1}'), User $user: account locked!"
fi
done
```
注意,去掉了第一个if语句后,需要将原代码中的第二个if移动到第一个if的位置,以保证逻辑正确。
#!/bin/bash users=$(cut -d: -f1 /etc/passwd) for user in $users do if [[ $(getent passwd $user | cut -d: -f3) -ge 1000 ]] then if [[ $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ') == "never" ]] then echo "$user: Password never expires" else expire_date=$(date -d "$(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" +%s) current_date=$(date +%s) if [[ $expire_date -lt $current_date ]] then echo "$(hostname -I | awk '{print $1}'),$user: Password has expired" else echo "$user: Password will expire on $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" fi fi else echo "" account_status=$(passwd -S $user | awk '{print $2}') if [[ "$account_status" == "L" ]]; then echo "$(hostname -I | awk '{print $1}'),User $user: account locked!" fi done语法问题
在第27行缺少一个 `fi` 关键字来结束第20行的 `if` 语句。同时,第24行的 `echo` 命令中,应该把逗号放在双引号内,否则会被视为两个参数。正确的脚本如下:
```
#!/bin/bash
users=$(cut -d: -f1 /etc/passwd)
for user in $users
do
if [[ $(getent passwd $user | cut -d: -f3) -ge 1000 ]]
then
if [[ $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ') == "never" ]]
then
echo "$user: Password never expires"
else
expire_date=$(date -d "$(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" +%s)
current_date=$(date +%s)
if [[ $expire_date -lt $current_date ]]
then
echo "$(hostname -I | awk '{print $1}'), $user: Password has expired"
else
echo "$user: Password will expire on $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')"
fi
fi
else
account_status=$(passwd -S $user | awk '{print $2}')
if [[ "$account_status" == "L" ]]; then
echo "$(hostname -I | awk '{print $1}'), User $user: account locked!"
fi
fi
done
```
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