囚徒困境合作、背叛、以牙还牙、随机python代码

下面是一个实现囚徒困境合作、背叛、以牙还牙和随机策略的 Python 代码示例：

import random

# 策略：合作
def cooperate(last_opponent_action):
    return 'cooperate'

# 策略：背叛
def defect(last_opponent_action):
    return 'defect'

# 策略：以牙还牙
def tit_for_tat(last_opponent_action):
    if last_opponent_action == 'cooperate':
        return 'cooperate'
    else:
        return 'defect'

# 策略：随机
def random_choice(last_opponent_action):
    return random.choice(['cooperate', 'defect'])

# 主函数
def play_game(player1, player2, num_rounds):
    p1_cooperated = True
    p2_cooperated = True
    p1_score = 0
    p2_score = 0

    for i in range(num_rounds):
        p1_action = player1('cooperate' if p1_cooperated else 'defect')
        p2_action = player2('cooperate' if p2_cooperated else 'defect')

        if p1_action == 'cooperate' and p2_action == 'cooperate':
            p1_score += 3
            p2_score += 3
            p1_cooperated = True
            p2_cooperated = True
        elif p1_action == 'cooperate' and p2_action == 'defect':
            p1_score += 0
            p2_score += 5
            p1_cooperated = True
            p2_cooperated = False
        elif p1_action == 'defect' and p2_action == 'cooperate':
            p1_score += 5
            p2_score += 0
            p1_cooperated = False
            p2_cooperated = True
        else:
            p1_score += 1
            p2_score += 1
            p1_cooperated = False
            p2_cooperated = False

    return p1_score, p2_score

# 测试代码
if __name__ == '__main__':
    player1 = cooperate
    player2 = defect
    num_rounds = 5

    p1_score, p2_score = play_game(player1, player2, num_rounds)
    print(f'Player 1 score: {p1_score}')
    print(f'Player 2 score: {p2_score}')

    player1 = tit_for_tat
    player2 = tit_for_tat

    p1_score, p2_score = play_game(player1, player2, num_rounds)
    print(f'Player 1 score: {p1_score}')
    print(f'Player 2 score: {p2_score}')

    player1 = random_choice
    player2 = random_choice

    p1_score, p2_score = play_game(player1, player2, num_rounds)
    print(f'Player 1 score: {p1_score}')
    print(f'Player 2 score: {p2_score}')

这个代码实现了一个囚徒困境游戏，其中有四种不同的策略：合作、背叛、以牙还牙和随机。在每一轮中，两个玩家都会根据它们的策略来做出决策，然后根据它们的决策来更新分数和合作状态。最后，输出两个玩家的得分。