囚徒困境合作、背叛、以牙还牙、随机策略python代码

以下是一个实现囚徒困境游戏的Python代码示例，其中包括合作、背叛、以牙还牙和随机策略：

import random

# 定义囚徒困境游戏
def prisoner_dilemma(p1, p2):
    if p1 == 'C' and p2 == 'C':
        return (3, 3)
    elif p1 == 'C' and p2 == 'D':
        return (0, 5)
    elif p1 == 'D' and p2 == 'C':
        return (5, 0)
    elif p1 == 'D' and p2 == 'D':
        return (1, 1)

# 定义策略函数
def cooperate_strategy(opponent_moves):
    return 'C'

def defect_strategy(opponent_moves):
    return 'D'

def tit_for_tat_strategy(opponent_moves):
    if opponent_moves:
        return opponent_moves[-1]
    else:
        return 'C'

def random_strategy(opponent_moves):
    return random.choice(['C', 'D'])

# 测试策略函数
strategies = [cooperate_strategy, defect_strategy, tit_for_tat_strategy, random_strategy]
for strategy in strategies:
    score = 0
    for i in range(10):
        my_move = strategy([])
        opponent_move = random_strategy([])
        my_score, opponent_score = prisoner_dilemma(my_move, opponent_move)
        score += my_score
    print(f"Strategy {strategy.__name__} scores {score}")

在这个示例中，我们首先定义了囚徒困境游戏的规则，然后定义了四种不同的策略函数：合作、背叛、以牙还牙和随机策略。最后，我们对每一个策略函数进行了测试，并输出了它的得分。