List<String> list = Arrays.asList(province); for (String str : list) { Matcher matcher = pattern.matcher(str); if (matcher.matches()) { province=str; } }什么意思
时间: 2024-02-10 16:33:41 浏览: 25
这段代码的作用是匹配一个正则表达式模式并将其应用于字符串列表中的所有字符串。具体来说,将一个名为 `province` 的字符串转换为字符串列表,然后对列表中的每个字符串应用一个名为 `pattern` 的正则表达式模式。如果模式匹配,则将 `province` 的值设置为此字符串。最终结果是将 `province` 重置为与正则表达式模式匹配的最后一个字符串。
相关问题
public static String findChannels(List<String> lines, String audioLine) throws EncoderParseException { String channels = RegexUtil.search(audioLine, "Hz,\\s*\\d+\\.\\d+"); String chane=RegexUtil.search(channels,"\\d+\\.\\d+"); List<String> ch= Arrays.asList(chane.split("\\.")); if (ch.size() == 0) throwParseError(lines, "AudioInfo-channels"); if (ch.size() == 1) return ch.get(0); return String.valueOf(Integer.parseInt(ch.get(0))*10+Integer.parseInt(ch.get(1))); }代码优化
可以考虑使用正则表达式的分组功能来直接获取到小数点前后的数字,而不需要再将字符串进行拆分和转换。代码如下:
```
public static String findChannels(List<String> lines, String audioLine) throws EncoderParseException {
String channels = RegexUtil.search(audioLine, "Hz,\\s*(\\d+\\.\\d+)");
if (channels == null) {
throwParseError(lines, "AudioInfo-channels");
}
Matcher matcher = Pattern.compile("(\\d+)\\.(\\d+)").matcher(channels);
if (matcher.find()) {
int integerPart = Integer.parseInt(matcher.group(1));
int decimalPart = Integer.parseInt(matcher.group(2));
return String.valueOf(integerPart * 10 + decimalPart);
} else {
throwParseError(lines, "AudioInfo-channels");
}
}
```
这样代码更简洁,也更易读。同时,对于没有找到数字或者数字格式不正确的情况,都会抛出解析异常,避免了返回空字符串或者错误的结果。
换一种方式获取项目名称的代码:@Override public List<ProjectCountVO> projectCount(String beginTime, String endTime, Integer forceType, String projectId) { // 查询任务列表 List<TaskTask> taskTaskList = this.listStatisticsTask(beginTime, endTime, forceType, projectId); if (CollectionUtil.isEmpty(taskTaskList)) { return Collections.emptyList(); } List<ProjectCountVO> result = new ArrayList<>(); // 将任务按照项目ID分组 Map<String, List<TaskTask>> projectTaskMap = taskTaskList.stream().collect(Collectors.groupingBy(TaskTask::getProjectId)); //查询项目名称 String bspToken = RequestHeaderHolder.getBspToken(); String bspUserId = RequestHeaderHolder.getUserId(); String bspUserEnvId = RequestHeaderHolder.getCompanyId(); String bspUserTenant = RequestHeaderHolder.getCompanyId(); String companyId = RequestHeaderHolder.getCompanyId(); ProjectCondition projectCondition = new ProjectCondition(); projectCondition.setAppId("23031408164321600"); projectCondition.setCompanyId(companyId); projectCondition.setDesignStatusList(Arrays.asList(2,3)); projectCondition.setPageSize(-1); projectCondition.setUserId(bspUserId); QueryAllProject queryAllProject = applicationServicePlatformClientProxy.listUserProject(bspToken, bspUserId, bspUserEnvId, bspUserTenant, projectCondition); for (Map.Entry<String, List<TaskTask>> projectTaskEntry : projectTaskMap.entrySet()) { projectId = projectTaskEntry.getKey(); ProjectCountVO projectCountVO = new ProjectCountVO(); projectCountVO.setId(projectId); String projectName = queryAllProject.getProjectList().stream() .filter(project -> project.getId().equals(projectId)) .findFirst() .map(Project::getName) .orElse(""); projectCountVO.setName(projectName); List<TaskTask> taskList = projectTaskEntry.getValue(); projectCountVO.setTaskCount(taskList.size()); Integer problemCount = CollectionUtil.isEmpty(taskList) ? 0 : taskList.stream() .collect(Collectors.summingInt(task -> Optional.ofNullable(task.getProblemNum()).orElse(0))); projectCountVO.setProblemCount(problemCount); result.add(projectCountVO); }
可以尝试使用正则表达式来获取项目名称,假设项目名称是以"projectName ="开头,";"结尾的字符串,可以使用以下代码:
```java
String regex = "projectName =([^;]*)";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(code);
if (matcher.find()) {
String projectName = matcher.group(1).trim();
System.out.println("Project Name: " + projectName);
}
```
其中,`code`是你提供的代码字符串。这个代码会提取出第一个匹配到的项目名称。