用整型数组表示10进制大整数(超过2^32的整数),数组的每个元素存储大整数的一位数字,实现大整数的加减法。
时间: 2024-01-22 11:19:20 浏览: 28
可以使用数组模拟计算大整数的加减法。以下是具体实现:
```c++
#include <iostream>
#include <vector>
using namespace std;
// 将整数转换为数组表示
vector<int> convertToArray(long long num) {
vector<int> arr;
while (num > 0) {
arr.push_back(num % 10);
num /= 10;
}
return arr;
}
// 将数组表示的整数转换为长整数
long long convertToLong(vector<int> arr) {
long long num = 0;
for (int i = arr.size() - 1; i >= 0; i--) {
num = num * 10 + arr[i];
}
return num;
}
// 计算两个数组表示的整数的和,返回结果的数组形式
vector<int> add(vector<int> a, vector<int> b) {
vector<int> res;
int carry = 0;
int i = 0, j = 0;
while (i < a.size() || j < b.size()) {
int sum = carry;
if (i < a.size()) sum += a[i++];
if (j < b.size()) sum += b[j++];
res.push_back(sum % 10);
carry = sum / 10;
}
if (carry > 0) res.push_back(carry);
return res;
}
// 判断a是否大于等于b
bool greaterOrEqual(vector<int> a, vector<int> b) {
if (a.size() != b.size()) return a.size() > b.size();
for (int i = a.size() - 1; i >= 0; i--) {
if (a[i] != b[i]) return a[i] > b[i];
}
return true;
}
// 计算两个数组表示的整数的差,返回结果的数组形式
vector<int> subtract(vector<int> a, vector<int> b) {
vector<int> res;
int borrow = 0;
int i = 0, j = 0;
while (i < a.size() || j < b.size()) {
int diff = borrow;
if (i < a.size()) diff += a[i++];
if (j < b.size()) diff -= b[j++];
if (diff < 0) {
diff += 10;
borrow = -1;
} else {
borrow = 0;
}
res.push_back(diff);
}
while (res.size() > 1 && res.back() == 0) {
res.pop_back();
}
return res;
}
int main() {
long long a, b;
cin >> a >> b;
// 将a和b转换为数组表示
vector<int> arrA = convertToArray(a);
vector<int> arrB = convertToArray(b);
// 计算a+b和a-b并输出
auto arrSum = add(arrA, arrB);
auto arrDiff = greaterOrEqual(arrA, arrB) ? subtract(arrA, arrB) : subtract(arrB, arrA);
cout << "a + b = " << convertToLong(arrSum) << endl;
cout << "a - b = " << convertToLong(arrDiff) << endl;
return 0;
}
```
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