% 定义变量范围 x_range = -10:0.1:10; y_range = -10:0.1:10; z_range = -10:0.1:10; % 初始化解数组 sols = []; % 循环计算 for i = 1:length(x_range) for j = 1:length(y_range) for k = 1:length(z_range) x = x_range(i); y = y_range(j); z = z_range(k); eqn1 = 513.85 == sqrt(3.((x-y)^2+(y-z)^2+(z-x)^2)/6); eqn2 = (x + y+z)/3/sqrt(3.((x-y)^2+(y-z)^2+(z-x)^2)/6) == sqrt(3)/3; eqn3 = (3sqrt(3)/2/27)(x.*y.z-(x+y+z).(x.*y+y.z+z.x)/3+(2.(x+y+z)^3)./27)... ./(2/3(((x-y)^2+(y-z)^2+(z-x)^2)/6)^(3/2)) == 0; sol = solve([eqn1, eqn2, eqn3], [x, y, z]); if ~isempty(sol) sols = [sols; [double(sol.x), double(sol.y), double(sol.z)]]; end end end end这段代码运行报错
时间: 2023-08-01 08:15:20 浏览: 155
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这段代码运行报错是因为在eqn1、eqn2和eqn3的计算中有一些语法错误,下面是修正后的代码:
```matlab
% 定义变量范围
x_range = -10:0.1:10;
y_range = -10:0.1:10;
z_range = -10:0.1:10;
% 初始化解数组
sols = [];
% 循环计算
for i = 1:length(x_range)
for j = 1:length(y_range)
for k = 1:length(z_range)
x = x_range(i);
y = y_range(j);
z = z_range(k);
eqn1 = 513.85 == sqrt(3*((x-y)^2+(y-z)^2+(z-x)^2)/6);
eqn2 = (x + y + z)/3/sqrt(3*((x-y)^2+(y-z)^2+(z-x)^2)/6) == sqrt(3)/3;
eqn3 = (3*sqrt(3)/2/27)*(x.*y.*z-(x+y+z).*(x.*y+y.*z+z.*x)/3+(2.*(x+y+z)^3)./27)...
./(2/3*(((x-y)^2+(y-z)^2+(z-x)^2)/6)^(3/2)) == 0;
sol = solve([eqn1, eqn2, eqn3], [x, y, z]);
if ~isempty(sol)
sols = [sols; [double(sol.x), double(sol.y), double(sol.z)]];
end
end
end
end
```
修正后的代码中,eqn1、eqn2和eqn3的表达式中乘号使用了点乘号(.*),加号使用了点加号(.+),并且去掉了一些多余的括号,这些都是语法上的错误。
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