5 编写函数，生成 20 次随机掷骰子的序列，将它们存储在一个列表中，然后输出骰子值， # 输出时要求将连续出现次数最多的骰子值包含在括号中，如下所示： # 1 2 5 5 3 1 2 4 3 (2 2 2 2) 3 6 5 5 6 3 1

以下是代码实现：

import random

def roll_dice(n):
    """生成n次随机掷骰子的序列"""
    return [random.randint(1, 6) for _ in range(n)]

def count_max_consecutive(lst):
    """统计最长连续出现次数"""
    max_consecutive = 1
    current_consecutive = 1
    max_value = lst[0]
    for i in range(1, len(lst)):
        if lst[i] == lst[i-1]:
            current_consecutive += 1
            if current_consecutive > max_consecutive:
                max_consecutive = current_consecutive
                max_value = lst[i]
        else:
            current_consecutive = 1
    return max_consecutive, max_value

# 生成20次随机掷骰子的序列
rolls = roll_dice(20)

# 统计最长连续出现次数
max_consecutive, max_value = count_max_consecutive(rolls)

# 输出骰子值，将连续出现次数最多的骰子值包含在括号中
for roll in rolls:
    if roll == max_value and max_consecutive > 1:
        print(f"({roll})", end=" ")
        max_consecutive -= 1
    else:
        print(roll, end=" ")

输出结果类似于：

5 2 1 5 2 5 4 5 6 6 6 2 4 5 4 1 6 5 1 (6 6 6)