给出一个完整的c语言程序,让其能实现DES算法。满足以下要求:每个学生输入自己的学号和“班级”,给出5种密钥的加密结果。从0x00000010-0x0000001F中选5种密钥,或随机生成16个密钥。

时间: 2023-06-24 09:03:43 浏览: 41
由于DES算法的实现比较复杂,需要大量的代码,我这里仅提供一个简化版的DES算法实现,仅供参考。 ```c #include <stdio.h> #include <stdlib.h> #include <string.h> #define ENCRYPT_MODE 0 #define DECRYPT_MODE 1 typedef unsigned char byte; typedef unsigned int uint; // Initial Permutation Table const byte IP[] = { 58, 50, 42, 34, 26, 18, 10, 2, 60, 52, 44, 36, 28, 20, 12, 4, 62, 54, 46, 38, 30, 22, 14, 6, 64, 56, 48, 40, 32, 24, 16, 8, 57, 49, 41, 33, 25, 17, 9, 1, 59, 51, 43, 35, 27, 19, 11, 3, 61, 53, 45, 37, 29, 21, 13, 5, 63, 55, 47, 39, 31, 23, 15, 7 }; // Final Permutation Table const byte FP[] = { 40, 8, 48, 16, 56, 24, 64, 32, 39, 7, 47, 15, 55, 23, 63, 31, 38, 6, 46, 14, 54, 22, 62, 30, 37, 5, 45, 13, 53, 21, 61, 29, 36, 4, 44, 12, 52, 20, 60, 28, 35, 3, 43, 11, 51, 19, 59, 27, 34, 2, 42, 10, 50, 18, 58, 26, 33, 1, 41, 9, 49, 17, 57, 25 }; // Permuted Choice 1 Table const byte PC1[] = { 57, 49, 41, 33, 25, 17, 9, 1, 58, 50, 42, 34, 26, 18, 10, 2, 59, 51, 43, 35, 27, 19, 11, 3, 60, 52, 44, 36, 63, 55, 47, 39, 31, 23, 15, 7, 62, 54, 46, 38, 30, 22, 14, 6, 61, 53, 45, 37, 29, 21, 13, 5, 28, 20, 12, 4 }; // Permuted Choice 2 Table const byte PC2[] = { 14, 17, 11, 24, 1, 5, 3, 28, 15, 6, 21, 10, 23, 19, 12, 4, 26, 8, 16, 7, 27, 20, 13, 2, 41, 52, 31, 37, 47, 55, 30, 40, 51, 45, 33, 48, 44, 49, 39, 56, 34, 53, 46, 42, 50, 36, 29, 32 }; // Expansion (E) Table const byte E[] = { 32, 1, 2, 3, 4, 5, 4, 5, 6, 7, 8, 9, 8, 9, 10, 11, 12, 13, 12, 13, 14, 15, 16, 17, 16, 17, 18, 19, 20, 21, 20, 21, 22, 23, 24, 25, 24, 25, 26, 27, 28, 29, 28, 29, 30, 31, 32, 1 }; // Substitution Boxes (S-boxes) const byte S[8][4][16] = { // S1 { {14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7}, {0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8}, {4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0}, {15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13} }, // S2 { {15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10}, {3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5}, {0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15}, {13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9} }, // S3 { {10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8}, {13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1}, {13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7}, {1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12} }, // S4 { {7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15}, {13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9}, {10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4}, {3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14} }, // S5 { {2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9}, {14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6}, {4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14}, {11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3} }, // S6 { {12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11}, {10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8}, {9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6}, {4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13} }, // S7 { {4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1}, {13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6}, {1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2}, {6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12} }, // S8 { {13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7}, {1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2}, {7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8}, {2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11} } }; // Permutation (P) Table const byte P[] = { 16, 7, 20, 21, 29, 12, 28, 17, 1, 15, 23, 26, 5, 18, 31, 10, 2, 8, 24, 14, 32, 27, 3, 9, 19, 13, 30, 6, 22, 11, 4, 25 }; // Initial Permutation Inverse Table const byte IP_INV[] = { 40, 8, 48, 16, 56, 24, 64, 32, 39, 7, 47, 15, 55, 23, 63, 31, 38, 6, 46, 14, 54, 22, 62, 30, 37, 5, 45, 13, 53, 21, 61, 29, 36, 4, 44, 12, 52, 20, 60, 28, 35, 3, 43, 11, 51, 19, 59, 27, 34, 2, 42, 10, 50, 18, 58, 26, 33, 1, 41, 9, 49, 17, 57, 25 }; // Rotation Table for key schedule const byte R[] = { 1, 2, 4, 6, 8, 10, 12, 14, 15, 17, 19, 21, 23, 25, 27, 28 }; // Key Schedule void key_schedule(byte key[], byte subkeys[][6]) { byte C[28], D[28], CD[56]; byte K[48]; // Permuted Choice 1 for (int i = 0; i < 28; i++) { C[i] = key[PC1[i] - 1]; D[i] = key[PC1[i + 28] - 1]; } // Generate 16 subkeys for (int i = 0; i < 16; i++) { // Rotate C and D byte tmp1 = C[0], tmp2 = D[0]; for (int j = 0; j < 27; j++) { C[j] = C[j + 1]; D[j] = D[j + 1]; } C[27] = tmp1; D[27] = tmp2; // Permuted Choice 2 for (int j = 0; j < 48; j++) { int idx = PC2[j] - 1; if (idx < 28) { K[j] = C[idx]; } else { K[j] = D[idx - 28]; } } memcpy(subkeys[i], K, 6); } } // Expansion (E) Function void expand(byte R[], byte E_R[]) { for (int i = 0; i < 48; i++) { E_R[i] = R[E[i] - 1]; } } // XOR Function void xor(byte a[], byte b[], byte c[], int len) { for (int i = 0; i < len; i++) { c[i] = a[i] ^ b[i]; } } // Substitution (S) Function void substitute(byte B[], byte S_B[]) { for (int i = 0; i < 8; i++) { int row = (B[i * 6] << 1) + B[i * 6 + 5]; int col = (B[i * 6 + 1] << 3) + (B[i * 6 + 2] << 2) + (B[i * 6 + 3] << 1) + B[i * 6 + 4]; int val = S[i][row][col]; S_B[i * 4] = (val & 8) >> 3; S_B[i * 4 + 1] = (val & 4) >> 2; S_B[i * 4 + 2] = (val & 2) >> 1; S_B[i * 4 + 3] = val & 1; } } // Permutation (P) Function void permute(byte B[], byte P_B[]) { for (int i = 0; i < 32; i++) { P_B[i] = B[P[i] - 1]; } } // Initial Permutation (IP) Function void initial_permutation(byte plaintext[], byte IP_text[]) { for (int i = 0; i < 64; i++) { IP_text[i] = plaintext[IP[i] - 1]; } } // Final Permutation (FP) Function void final_permutation(byte ciphertext[], byte FP_text[]) { for (int i = 0; i < 64; i++) { FP_text[i] = ciphertext[FP[i] - 1]; } } // DES Round Function void round_func(byte plaintext[], byte key[], byte ciphertext[]) { byte L[32], R[32], E_R[48], K[48], B[8], S_B[32], P_B[32]; // Split plaintext into L and R memcpy(L, plaintext, 32); memcpy(R, plaintext + 32, 32); // Expand R to 48 bits expand(R, E_R); //

相关推荐

最新推荐

recommend-type

使用java自带des加密算法实现文件加密和字符串加密

主要介绍了使用java自带des加密算法实现文件加密和字符串加密的示例,需要的朋友可以参考下
recommend-type

C语言实现DES加密解密算法

DES加密解密算法的C语言实现,只要调用函数,即可实现数据的加密解密,我已经在DSP上实现。
recommend-type

C语言使用openSSL库DES模块实现加密功能详解

主要介绍了C语言使用openSSL库DES模块实现加密功能,简单讲解了DES加密的相关概念,并结合实例形式分析了DES加密的具体实现技巧,需要的朋友可以参考下
recommend-type

Python基于DES算法加密解密实例

主要介绍了Python基于DES算法加密解密实现方法,以实例形式分析了DES算法实现加密解密的相关技巧,需要的朋友可以参考下
recommend-type

Python实现常见的几种加密算法(MD5,SHA-1,HMAC,DES/AES,RSA和ECC)

主要介绍了Python实现常见的几种加密算法,文中通过示例代码介绍的非常详细,对大家的学习或者工作具有一定的参考学习价值,需要的朋友们下面随着小编来一起学习学习吧
recommend-type

zigbee-cluster-library-specification

最新的zigbee-cluster-library-specification说明文档。
recommend-type

管理建模和仿真的文件

管理Boualem Benatallah引用此版本:布阿利姆·贝纳塔拉。管理建模和仿真。约瑟夫-傅立叶大学-格勒诺布尔第一大学,1996年。法语。NNT:电话:00345357HAL ID:电话:00345357https://theses.hal.science/tel-003453572008年12月9日提交HAL是一个多学科的开放存取档案馆,用于存放和传播科学研究论文,无论它们是否被公开。论文可以来自法国或国外的教学和研究机构,也可以来自公共或私人研究中心。L’archive ouverte pluridisciplinaire
recommend-type

实现实时数据湖架构:Kafka与Hive集成

![实现实时数据湖架构:Kafka与Hive集成](https://img-blog.csdnimg.cn/img_convert/10eb2e6972b3b6086286fc64c0b3ee41.jpeg) # 1. 实时数据湖架构概述** 实时数据湖是一种现代数据管理架构,它允许企业以低延迟的方式收集、存储和处理大量数据。与传统数据仓库不同,实时数据湖不依赖于预先定义的模式,而是采用灵活的架构,可以处理各种数据类型和格式。这种架构为企业提供了以下优势: - **实时洞察:**实时数据湖允许企业访问最新的数据,从而做出更明智的决策。 - **数据民主化:**实时数据湖使各种利益相关者都可
recommend-type

SPDK_NVMF_DISCOVERY_NQN是什么 有什么作用

SPDK_NVMF_DISCOVERY_NQN 是 SPDK (Storage Performance Development Kit) 中用于查询 NVMf (Non-Volatile Memory express over Fabrics) 存储设备名称的协议。NVMf 是一种基于网络的存储协议,可用于连接远程非易失性内存存储器。 SPDK_NVMF_DISCOVERY_NQN 的作用是让存储应用程序能够通过 SPDK 查询 NVMf 存储设备的名称,以便能够访问这些存储设备。通过查询 NVMf 存储设备名称,存储应用程序可以获取必要的信息,例如存储设备的IP地址、端口号、名称等,以便能
recommend-type

JSBSim Reference Manual

JSBSim参考手册,其中包含JSBSim简介,JSBSim配置文件xml的编写语法,编程手册以及一些应用实例等。其中有部分内容还没有写完,估计有生之年很难看到完整版了,但是内容还是很有参考价值的。