发送xml格式报文怎么写？

在Apache HttpClient 4.5.14中，如果你想发送XML格式的报文（例如通过POST请求），你可以使用`HttpEntityEnclosingRequestBase`类，配合`MultipartEntityBuilder`构建一个`StringRequestEntity`，然后设置到`HttpPost`实例上。下面是一个示例：

import org.apache.http.HttpEntity;
import org.apache.http.client.methods.CloseableHttpResponse;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.mime.MultipartEntityBuilder;
import org.apache.http.entity.mime.content.StringBody;
import org.apache.http.impl.client.CloseableHttpClient;
import org.apache.http.impl.client.HttpClients;
import org.apache.http.util.EntityUtils;

public class SendXmlHttpPost {
    private static final CloseableHttpClient httpClient = HttpClients.createDefault();

    public void sendXmlPost(String url, String xmlData) throws Exception {
        // 创建HttpPost请求
        HttpPost httpPost = new HttpPost(url);

        // 构建XML数据部分
        MultipartEntityBuilder builder = MultipartEntityBuilder.create();
        builder.addPart("data", new StringBody(xmlData, ContentType.APPLICATION_XML));

        // 设置请求体为XML多部分实体
        HttpEntity entity = builder.build();
        httpPost.setEntity(entity);

        try (CloseableHttpResponse response = httpClient.execute(httpPost)) {
            int statusCode = response.getStatusLine().getStatusCode();
            if (statusCode >= 200 && statusCode < 300) {
                System.out.println("Response status: " + statusCode);
                HttpEntity responseEntity = response.getEntity();
                if (responseEntity != null) {
                    String responseBody = EntityUtils.toString(responseEntity, "UTF-8");
                    System.out.println("Response body: " + responseBody);
                }
            } else {
                throw new RuntimeException("Failed to execute request, status code: " + statusCode);
            }
        }
    }

    // 关闭连接池
    public void shutDown() throws IOException {
        httpClient.close();
    }
}

这里的`xmlData`是你想要发送的XML字符串。注意，你需要根据实际情况调整`contentType`和键值对。