一个结构体数组的一部分对另一个结构体数组的赋值

假设我们有两个结构体数组team1和team2，它们的结构体模板都是Player，现在要将team1中的前三个元素的值赋给team2中的后三个元素，可以使用循环遍历实现：

#include <stdio.h>
#include <string.h>

struct Player {
    char name[32];
    char sex[32];
    char position[32];
    float height;
    float weight;
};

int main() {
    struct Player team1[6] = {
        {"player1", "male", "forward", 180, 70},
        {"player2", "female", "guard", 170, 60},
        {"player3", "male", "center", 190, 80},
        {"player4", "female", "forward", 175, 65},
        {"player5", "male", "guard", 185, 75},
        {"player6", "female", "center", 180, 70}
    };
    struct Player team2[6];

    // 将team1中的前三个元素的值赋给team2中的后三个元素
    for (int i = 0; i < 3; i++) {
        strcpy(team2[i+3].name, team1[i].name);
        strcpy(team2[i+3].sex, team1[i].sex);
        strcpy(team2[i+3].position, team1[i].position);
        team2[i+3].height = team1[i].height;
        team2[i+3].weight = team1[i].weight;
    }

    // 输出team2中的元素
    for (int i = 0; i < 6; i++) {
        printf("name: %s, sex: %s, position: %s, height: %.2f, weight: %.2f\n", team2[i].name, team2[i].sex, team2[i].position, team2[i].height, team2[i].weight);
    }

    return 0;
}

输出结果为：

name: , sex: , position: , height: 0.00, weight: 0.00
name: , sex: , position: , height: 0.00, weight: 0.00
name: , sex: , position: , height: 0.00, weight: 0.00
name: player1, sex: male, position: forward, height: 180.00, weight: 70.00
name: player2, sex: female, position: guard, height: 170.00, weight: 60.00
name: player3, sex: male, position: center, height: 190.00, weight: 80.00