c语言1+1/2+1/3+...+1/100

以下是求解1+1/2+1/3+...+1/100的C语言程序：

#include <stdio.h>

int main() {
    int n = 100;
    float sum = 0;
    for (int j = 1; j <= n; j++) {
        sum = sum + 1.0 / j;
    }
    printf("前%d项的和为%.3f", n, sum);
    return 0;
}