C语言用while循环求1!+2+!+3!+4!+5!+6!)

以下是使用while循环求1!+2!+3!+4!+5!+6!的C语言代码：

#include <stdio.h>

int main() {
    int i = 1, j = 1, sum = 0;
    while (i <= 6) {
        j = 1;
        int temp = 1;
        while (j <= i) {
            temp *= j;
            j++;
        }
        sum += temp;
        i++;
    }
    printf("1!+2!+3!+4!+5!+6!=%d", sum);
    return 0;
}

相关问题

c语言求1!+2!+3!+4!+5!代码加运行结果用while和for循环写

以下是使用while和for循环分别实现求1!+2!+3!+4!+5!的C语言代码及运行结果：

使用while循环实现：

#include <stdio.h>
#include <stdlib.h>

int Factor(int n) //计算n的阶乘
{
    int result = 1;
    for (int i = 1; i <= n; i += 1) {
        result *= i;
    }
    return result;
}

int Factorsum_while(int n) //计算1!+2!+3!+...+n!的和
{
    int sum = 0;
    int i = 1;
    while (i <= n) {
        sum += Factor(i);
        i++;
    }
    return sum;
}

int main() {
    int result = Factorsum_while(5); //n为5
    printf("result = %d\n", result); //输出结果：result = 153
    system("pause");
    return 0;
}

使用for循环实现：

#include <stdio.h>
#include <stdlib.h>

int Factor(int n) //计算n的阶乘
{
    int result = 1;
    for (int i = 1; i <= n; i += 1) {
        result *= i;
    }
    return result;
}

int Factorsum_for(int n) //计算1!+2!+3!+...+n!的和
{
    int sum = 0;
    for (int i = 1; i <= n; i += 1) {
        sum += Factor(i);
    }
    return sum;
}

int main() {
    int result = Factorsum_for(5); //n为5
    printf("result = %d\n", result); //输出结果：result = 153
    system("pause");
    return 0;
}

用c语言求 1!+2!+3!+4!+5!+…+15！

可以使用for循环或者while循环来实现1!+2!+3!+4!+5!+…+15！的累加。具体代码如下：

方法一：使用for循环

#include <stdio.h>

int main()
{
    int i, n;
    long long sum = 0, factorial = 1;

    printf("请输入N的值：");
    scanf("%d", &n);

    for (i = 1; i <= n; i++) {
        factorial *= i;
        sum += factorial;
    }

    printf("1!+2!+3!+...+%d! = %lld\n", n, sum);

    return 0;
}

方法二：使用while循环

#include <stdio.h>

int main()
{
    int i = 1, n;
    long long sum = 0, factorial = 1;

    printf("请输入N的值：");
    scanf("%d", &n);

    while (i <= n) {
        factorial *= i;
        sum += factorial;
        i++;
    }

    printf("1!+2!+3!+...+%d! = %lld\n", n, sum);

    return 0;
}