poj1328java

根据您的问题，我理解您想了解POJ1328问题的Java解决方案。POJ1328是一个经典的问题，也被称为"雷达安装"问题，它涉及到在一个二维平面上安装雷达以覆盖所有岛屿的最小雷达数量。以下是一个Java解决方案的示例代码：

import java.util.Arrays;
import java.util.Comparator;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int caseNum = 1;
        while (true) {
            int n = scanner.nextInt();
            if (n == 0) {
                break;
            }
            Island[] islands = new Island[n];
            for (int i = 0; i < n; i++) {
                int x = scanner.nextInt();
                int y = scanner.nextInt();
                islands[i] = new Island(x, y);
            }
            int radarNum = getRadarNum(islands);
            System.out.println("Case " + caseNum + ": " + radarNum);
            caseNum++;
        }
    }

    private static int getRadarNum(Island[] islands) {
        Arrays.sort(islands, Comparator.comparingInt(Island::getRight));
        int radarNum = 1;
        int rightMost = islands[0].getRight();
        for (int i = 1; i < islands.length; i++) {
            if (islands[i].getLeft() > rightMost) {
                radarNum++;
                rightMost = islands[i].getRight();
            } else {
                rightMost = Math.min(rightMost, islands[i].getRight());
            }
        }
        return radarNum;
    }

    static class Island {
        private int left;
        private int right;

        public Island(int left, int right) {
            this.left = left;
            this.right = right;
        }

        public int getLeft() {
            return left;
        }

        public int getRight() {
            return right;
        }
    }
}

这段代码通过输入岛屿的坐标，计算出需要安装的最小雷达数量，并输出结果。它使用了排序和贪心算法的思想来解决问题。