c++简易井字棋小游戏

好的，以下是一个简易的C++井字棋小游戏代码，供你参考：

#include <iostream>
using namespace std;

char board[3][3] = {{'1', '2', '3'}, {'4', '5', '6'}, {'7', '8', '9'}};
char player = 'X';

void draw_board() {
    cout << "  " << board[0][0] << " | " << board[0][1] << " | " << board[0][2] << endl;
    cout << " -----------" << endl;
    cout << "  " << board[1][0] << " | " << board[1][1] << " | " << board[1][2] << endl;
    cout << " -----------" << endl;
    cout << "  " << board[2][0] << " | " << board[2][1] << " | " << board[2][2] << endl;
}

bool check_win() {
    for (int i = 0; i < 3; i++) {
        if (board[i][0] == board[i][1] && board[i][1] == board[i][2])
            return true;
        if (board[0][i] == board[1][i] && board[1][i] == board[2][i])
            return true;
    }
    if (board[0][0] == board[1][1] && board[1][1] == board[2][2])
        return true;
    if (board[0][2] == board[1][1] && board[1][1] == board[2][0])
        return true;
    return false;
}

int main() {
    int choice;
    cout << "Welcome to Tic-Tac-Toe!" << endl;
    draw_board();
    while (true) {
        cout << "Player " << player << ", please enter your choice: ";
        cin >> choice;
        int row = (choice - 1) / 3;
        int col = (choice - 1) % 3;
        if (board[row][col] == 'X' || board[row][col] == 'O') {
            cout << "Invalid move! Please try again." << endl;
            continue;
        }
        board[row][col] = player;
        draw_board();
        if (check_win()) {
            cout << "Player " << player << " wins!" << endl;
            break;
        }
        if (player == 'X')
            player = 'O';
        else
            player = 'X';
    }
    return 0;
}

这个代码实现了一个简单的C++井字棋小游戏。在游戏开始时，程序会打印出一个3x3的棋盘。玩家可以轮流输入数字来选择位置，程序会在棋盘上添加“X”或“O”。如果某个玩家连成了一条直线，程序会宣布其获胜。如果棋盘填满了但没有玩家获胜，程序会宣布平局。