Integer.parseInt()
时间: 2024-05-07 15:16:15 浏览: 6
Integer.parseInt() is a method in Java that takes a string as input and converts it into an integer. It is used to convert a string representation of an integer into its corresponding integer value. If the string cannot be parsed as an integer, a NumberFormatException is thrown.
For example, the following code converts the string "123" into the integer value 123:
```
String str = "123";
int num = Integer.parseInt(str);
```
The variable `num` would have the value of 123 after the execution of the above code.
相关问题
Integer.parseInt
`Integer.parseInt()` 是 Java 中将字符串转换为整数类型的方法,其语法如下:
```java
int intValue = Integer.parseInt(str);
```
其中,`str` 为要转换的字符串,`intValue` 为转换后的整数值。
需要注意的是,如果 `str` 无法转换为整数类型,`Integer.parseInt()` 方法会抛出 `NumberFormatException` 异常,需要进行异常处理。
示例代码如下:
```java
String str = "123";
int intValue = Integer.parseInt(str);
System.out.println(intValue); // 输出 123
```
另外,`Integer.parseInt()` 方法还支持设置进制数,可以将指定进制的字符串转换为整数类型。方法语法如下:
```java
int intValue = Integer.parseInt(str, radix);
```
其中,`radix` 为进制数,可以是 2、8、10 或 16。如果不指定进制数,则默认为 10。
示例代码如下:
```java
String binaryStr = "1010";
int binaryIntValue = Integer.parseInt(binaryStr, 2);
System.out.println(binaryIntValue); // 输出 10
String hexStr = "FF";
int hexIntValue = Integer.parseInt(hexStr, 16);
System.out.println(hexIntValue); // 输出 255
```
integer.parseint
The parseInt() method in Java is used to convert a string to an integer. It takes two arguments - the string to be converted and the radix (base) of the number system to be used.
Syntax:
```
public static int parseInt(String str, int radix)
```
Example:
```
String str = "123";
int num = Integer.parseInt(str);
```
In this example, the string "123" is converted to an integer value of 123 using the parseInt() method.