运用Fortran语言设计,球体半径为R=5m,深度为D=20m,剩余密度为△o=0.3*103kg/m3,x和y坐标设置 从-100m到100m,以0.5m为间距。计算重力异常△g(G为万有引力常数
时间: 2024-11-09 07:23:35 浏览: 26
在Fortran语言中,你可以使用牛顿重力公式来计算重力异常,其基本形式是:
\[ \Delta g = -G * \frac{\rho_{\text{余}} V}{r^2} \]
其中:
- \( \Delta g \) 是重力异常,
- \( G \) 是万有引力常数 (通常取约为 6.674 × 10^-11 N·(m/kg)^2),
- \( \rho_{\text{余}} \) 是剩余密度,
- \( V \) 是体积 (球体体积),
- \( r \) 是从球心到某点的距离。
给定条件是:
- 半径 R = 5 m,
- 深度 D = 20 m,
- 剩余密度 \( \triangle o = 0.3 \times 10^3 \) kg/m³,
- x和y坐标的范围是从 -100 m 到 100 m,步长为 0.5 m.
首先,我们需要计算每个点到球心的距离 \( r \),因为不是所有点都在球体内部,所以需要判断距离是否小于等于半径加上深度。接下来,我们可以用一个二维数组来存储x和y坐标,并遍历这个数组计算每个点的\( \Delta g \)。
这是一个简单的示例代码片段:
```fortran
program GravityAnomaly
implicit none
real(8), parameter :: G = 6.674e-11, pi = 3.141592653589793
real(8) :: R, D, rho_o, dx, dy, r, g, delta_g
integer :: i, j
real(8), dimension(:,:), allocatable :: x_y_grid
! 初始化变量
R = 5.0d0
D = 20.0d0
rho_o = 0.3e3
dx = 0.5d0
dy = 0.5d0
! 创建x_y网格
allocate(x_y_grid(-100/dx+1:-100/dx+1, -100/dy+1:-100/dy+1))
do i = -100/dx+1, 100/dx+1
do j = -100/dy+1, 100/dy+1
r = sqrt(dx**2 * abs(i)**2 + dy**2 * abs(j)**2)
if (r <= R + D) then
r = R + D - r ! 如果在球体外部,使用有效长度
g = G * rho_o * (4.0/3.0 * pi * R**3) / r**2
delta_g = g
! 计算并存储重力异常值
x_y_grid(i, j) = delta_g
else
delta_g = 0.0 ! 点在球体外部,设重力异常为0
end if
end do
end do
! 打印或输出结果
! ...
end program GravityAnomaly
```
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