使用一项广度优先算法实现五子棋游戏的运行。要求：使用python编程，需要有图形化界面

在Python中实现五子棋游戏并采用广度优先搜索(BFS)策略，我们可以使用Tkinter库创建基本的图形用户界面(GUI)，而游戏的核心逻辑将利用BFS遍历树形结构，寻找最佳落子位置。以下是一个简单的步骤概述：

1. **导入所需库**:

import tkinter as tk
from queue import Queue

2. **创建棋盘和棋子类**:

class Board(tk.Canvas):
    def __init__(self, *args, **kwargs):
        super().__init__(*args, **kwargs)
        self.create_rectangle(0, 0, self.winfo_width(), self.winfo_height(), fill="white")
        self.board = [[' ' for _ in range(15)] for _ in range(15)]
        
class Stone(Board):
    pass

3. **定义BFS函数**:

def bfs(board, player, start, end):
    visited = set()
    q = Queue()
    q.put((start, []))
    
    while not q.empty():
        x, path = q.get()
        if (x, y) in visited or board[x][y] != player:
            continue
        
        path.append((x, y))
        if is_five_in_a_row(path, player):
            return path
        
        visited.add((x, y))
        for dx, dy in [(0, 1), (1, 0), (-1, 0), (0, -1)]:
            next_x, next_y = x + dx, y + dy
            if 0 <= next_x < 15 and 0 <= next_y < 15 and board[next_x][next_y] == ' ':
                q.put((next_x, path.copy()))
                
def is_five_in_a_row(path, player):
    # 检查路径上是否有五个连续的同色棋子
    for i in range(len(path)-4):
        if path[i:i+5] == [(x, y) for x, y in zip(*[iter(path[i:i+5])] * 2)]:
            return True
    return False

4. **绘制棋盘并处理玩家落子**:

root = tk.Tk()
board = Board(root, width=600, height=600)
player = "X"

def on_click(event):
    x = event.x // 60
    y = event.y // 60
    if board.board[x][y] == ' ':
        board.board[x][y] = player
        if player == "X":
            stone = Stone(root, create_polygon, x*60, y*60, 59)
        else:
            stone = Stone(root, create_circle, x*60, y*60, 28)
        stone.pack()

# ... (添加鼠标点击事件监听、更新UI等)

root.mainloop()

5. **使用BFS检查胜利条件并在必要时移动棋子**:
每次玩家落子后，都可以调用`bfs()`函数检查是否有胜利情况，如果没有，则轮到对手。