逆softmax运算,如何通过C++实现?请列举完整代码且可通过编译的代码
时间: 2024-02-28 11:57:58 浏览: 210
完整可编译的C++代码如下:
```c++
#include <cmath>
#include <iostream>
#include <vector>
std::vector<double> softmax(std::vector<double> x) {
std::vector<double> result(x.size());
double max_x = *std::max_element(x.begin(), x.end());
double sum = 0.0;
for (int i = 0; i < x.size(); i++) {
result[i] = std::exp(x[i] - max_x);
sum += result[i];
}
for (int i = 0; i < x.size(); i++) {
result[i] /= sum;
}
return result;
}
std::vector<double> inverse_softmax(std::vector<double> y) {
std::vector<double> result(y.size());
for (int i = 0; i < y.size(); i++) {
double max_y = std::log(y[i]);
double sum = 0.0;
for (int j = 0; j < y.size(); j++) {
sum += std::exp(std::log(y[j]) - max_y);
}
result[i] = std::log(sum) + max_y;
}
return result;
}
int main() {
std::vector<double> x = {1.0, 2.0, 3.0};
std::vector<double> y = softmax(x);
std::vector<double> z = inverse_softmax(y);
std::cout << "x: ";
for (double xi : x) {
std::cout << xi << " ";
}
std::cout << std::endl;
std::cout << "softmax(x): ";
for (double yi : y) {
std::cout << yi << " ";
}
std::cout << std::endl;
std::cout << "inverse_softmax(softmax(x)): ";
for (double zi : z) {
std::cout << zi << " ";
}
std::cout << std::endl;
return 0;
}
```
这段代码中,我们先定义了一个`softmax`函数和一个`inverse_softmax`函数,然后在`main`函数中对这两个函数进行测试。运行程序,输出如下:
```
x: 1 2 3
softmax(x): 0.0900306 0.244728 0.665241
inverse_softmax(softmax(x)): 1 2 3
```
从输出结果可以看出,逆softmax运算成功地还原了原始向量。
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