for(m=1;m<n;m++) { i=1; while(i<n) { i=i*2; } }
时间: 2023-12-30 18:05:59 浏览: 53
This code is incomplete as there is no closing bracket for the outer for loop. Without knowing the value of n, it is difficult to determine the purpose of this code. However, it appears to be a nested loop structure where the inner while loop iteratively doubles the value of i until it reaches or exceeds the value of n. The outer for loop likely controls the number of times the inner loop executes.
相关问题
for(m=1;m<n;m++) { i=1; while(i<n) { i=i*2; } }结果是多少
该代码存在语法错误,缺少循环条件的更新语句。应该将代码改为:
for (m=1; m<n; m++) {
i=1;
while (i<n) {
i=i*2;
}
}
此代码中,外层循环执行n-1次,内层循环执行log2(n)次。因此,总的执行次数为(n-1) * log2(n)。
#include <iostream> #include <cstring> #include <algorithm> #include <vector> using namespace std; const int N = 10; int n, m; int a[N]; int main() { cout << "请输入结点数:" << endl; while (cin >> n >> m) //输入图1、2的结点数 { if (m != n) { cout << "两图不同构!!!" << endl; continue; } //根据结点数n、m,动态生成两个二维数组来存图(使用邻接矩阵的方式) vector<int> w1(n + 1, 0); vector<vector<int> > g1(n + 1, w1); vector<int> w2(m + 1, 0); vector<vector<int> > g2(m + 1, w2); for (int i = 1; i <= n; i++) a[i] = i; //初始化a数组 for (int i = 1; i <= n; i++) //输入图1的邻接矩阵 for (int j = 1; j <= n; j++) cin >> g1[i][j]; for (int i = 1; i <= m; i++) //输入图2的邻接矩阵 for (int j = 1; j <= m; j++) cin >> g2[i][j]; //全排列 do { bool f = 0; int temp[N][N]; memset(temp, 0, sizeof temp); for (int i = 1; i <= n; i++) { for (int j = 1; j <= n; j++) { temp[i][j] = g1[a[i]][a[j]]; } } for (int i = 1; i <= n; i++) { for (int j = 1; j <= n; j++) { if (temp[i][j] != g2[i][j]) { f = 1; break; } } if (f == 1) break; } if (f == 0) cout << "两图同构^-^" << endl; } while (next_permutation(a + 1, a + 1 + n)); cout << "两图不同构!!!" << endl; } return 0; }简化的完整代码
这是一个判断两个图是否同构的程序,输入两个图的邻接矩阵,通过枚举两个图的节点的排列顺序,判断它们是否同构。如果是同构的,则输出"两图同构^-^",否则输出"两图不同构!!!"。
```cpp
#include <iostream>
#include <cstring>
#include <algorithm>
#include <vector>
using namespace std;
const int N = 10;
int n, m;
int a[N];
int main() {
cout << "请输入结点数:" << endl;
while (cin >> n >> m) { //输入图1、2的结点数
if (m != n) {
cout << "两图不同构!!!" << endl;
continue;
}
//根据结点数n、m,动态生成两个二维数组来存图(使用邻接矩阵的方式)
vector<int> w1(n + 1, 0);
vector<vector<int> > g1(n + 1, w1);
vector<int> w2(m + 1, 0);
vector<vector<int> > g2(m + 1, w2);
for (int i = 1; i <= n; i++) a[i] = i; //初始化a数组
for (int i = 1; i <= n; i++) //输入图1的邻接矩阵
for (int j = 1; j <= n; j++)
cin >> g1[i][j];
for (int i = 1; i <= m; i++) //输入图2的邻接矩阵
for (int j = 1; j <= m; j++)
cin >> g2[i][j];
//全排列
do {
bool f = 0;
int temp[N][N];
memset(temp, 0, sizeof temp);
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) {
temp[i][j] = g1[a[i]][a[j]];
}
}
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) {
if (temp[i][j] != g2[i][j]) {
f = 1;
break;
}
}
if (f == 1) break;
}
if (f == 0) cout << "两图同构^-^" << endl;
} while (next_permutation(a + 1, a + 1 + n));
cout << "两图不同构!!!" << endl;
}
return 0;
}
```