给定一个int数组，假设有10000个长度，里面放满1-100的随机整数。用java编程需要用串行循环计算和Executors框架两种方法，实现查找并输出该数组中50的出现个数，并且在程序中加个运行时间最后对比两种方法的执行速度。 。给出完整java代码

串行循环方法：

import java.util.Random;

public class SerialLoop {
    public static void main(String[] args) {
        Random random = new Random();
        int[] arr = new int[10000];
        for (int i = 0; i < arr.length; i++) {
            arr[i] = random.nextInt(100) + 1;
        }
        int count = 0;
        long start = System.currentTimeMillis();
        for (int i = 0; i < arr.length; i++) {
            if (arr[i] == 50) {
                count++;
            }
        }
        long end = System.currentTimeMillis();
        System.out.println("The number of 50 in the array is: " + count);
        System.out.println("Time taken: " + (end - start) + "ms");
    }
}

Executors框架方法：

import java.util.Random;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.atomic.AtomicInteger;

public class ExecutorsMethod {
    public static void main(String[] args) {
        Random random = new Random();
        int[] arr = new int[10000];
        for (int i = 0; i < arr.length; i++) {
            arr[i] = random.nextInt(100) + 1;
        }
        AtomicInteger count = new AtomicInteger(0);
        long start = System.currentTimeMillis();
        ExecutorService executorService = Executors.newFixedThreadPool(10);
        for (int i = 0; i < arr.length; i++) {
            executorService.execute(new Runnable() {
                @Override
                public void run() {
                    if (arr[i] == 50) {
                        count.incrementAndGet();
                    }
                }
            });
        }
        executorService.shutdown();
        while (!executorService.isTerminated()) {
            // waiting for all threads to finish
        }
        long end = System.currentTimeMillis();
        System.out.println("The number of 50 in the array is: " + count);
        System.out.println("Time taken: " + (end - start) + "ms");
    }
}