要求用C语言编写:1.先编写一个带结构的文件，存入电脑，要求第一行从左到右的内容依次是：姓名、地址、学号，每排每列对齐，没有对齐的地方用空格补齐。2.从电脑中能够读入这个带结构的文件，并进行删增改后，重新存入电脑，3.这个文件要有纵横结构，每横表示一个记录4. 编出来的代码要能够在c的运行界面进行后续的插入、删除和修改

好的，我可以帮你解决这个问题。以下是一个简单的实现：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define MAX_NAME_LEN 20
#define MAX_ADDRESS_LEN 50
#define MAX_ID_LEN 10
#define MAX_RECORDS 100

typedef struct {
    char name[MAX_NAME_LEN];
    char address[MAX_ADDRESS_LEN];
    char id[MAX_ID_LEN];
} Record;

int read_records(Record records[], int *n, const char *filename) {
    FILE *fp = fopen(filename, "r");
    if (fp == NULL) {
        return 0;
    }
    char buf[MAX_NAME_LEN + MAX_ADDRESS_LEN + MAX_ID_LEN + 3];
    int i = 0;
    while (fgets(buf, sizeof(buf), fp) != NULL) {
        char *name = strtok(buf, " ");
        char *address = strtok(NULL, " ");
        char *id = strtok(NULL, " ");
        if (name == NULL || address == NULL || id == NULL) {
            fclose(fp);
            return 0;
        }
        strcpy(records[i].name, name);
        strcpy(records[i].address, address);
        strcpy(records[i].id, id);
        i++;
    }
    fclose(fp);
    *n = i;
    return 1;
}

void print_records(const Record records[], int n) {
    printf("%-20s%-50s%-10s\n", "姓名", "地址", "学号");
    for (int i = 0; i < n; i++) {
        printf("%-20s%-50s%-10s\n", records[i].name, records[i].address, records[i].id);
    }
}

int write_records(const Record records[], int n, const char *filename) {
    FILE *fp = fopen(filename, "w");
    if (fp == NULL) {
        return 0;
    }
    for (int i = 0; i < n; i++) {
        fprintf(fp, "%-20s%-50s%-10s\n", records[i].name, records[i].address, records[i].id);
    }
    fclose(fp);
    return 1;
}

int find_record(const Record records[], int n, const char *id) {
    for (int i = 0; i < n; i++) {
        if (strcmp(records[i].id, id) == 0) {
            return i;
        }
    }
    return -1;
}

void insert_record(Record records[], int *n) {
    if (*n >= MAX_RECORDS) {
        printf("记录已满，无法插入！\n");
        return;
    }
    Record record;
    printf("请输入姓名、地址、学号：");
    scanf("%s %s %s", record.name, record.address, record.id);
    records[*n] = record;
    (*n)++;
}

void delete_record(Record records[], int *n) {
    char id[MAX_ID_LEN];
    printf("请输入要删除的学号：");
    scanf("%s", id);
    int pos = find_record(records, *n, id);
    if (pos == -1) {
        printf("找不到该学号的记录！\n");
        return;
    }
    for (int i = pos; i < *n - 1; i++) {
        records[i] = records[i + 1];
    }
    (*n)--;
}

void update_record(Record records[], int n) {
    char id[MAX_ID_LEN];
    printf("请输入要修改的学号：");
    scanf("%s", id);
    int pos = find_record(records, n, id);
    if (pos == -1) {
        printf("找不到该学号的记录！\n");
        return;
    }
    Record record;
    printf("请输入新的姓名、地址、学号：");
    scanf("%s %s %s", record.name, record.address, record.id);
    records[pos] = record;
}

int main() {
    Record records[MAX_RECORDS];
    int n = 0;
    if (!read_records(records, &n, "records.txt")) {
        printf("读取文件失败！\n");
        return 1;
    }
    while (1) {
        printf("请选择操作：\n");
        printf("1. 显示记录\n");
        printf("2. 插入记录\n");
        printf("3. 删除记录\n");
        printf("4. 修改记录\n");
        printf("5. 保存并退出\n");
        int choice;
        scanf("%d", &choice);
        switch (choice) {
            case 1:
                print_records(records, n);
                break;
            case 2:
                insert_record(records, &n);
                break;
            case 3:
                delete_record(records, &n);
                break;
            case 4:
                update_record(records, n);
                break;
            case 5:
                if (!write_records(records, n, "records.txt")) {
                    printf("保存文件失败！\n");
                    return 1;
                }
                printf("已保存并退出。\n");
                return 0;
            default:
                printf("无效操作！\n");
        }
    }
}

这个程序使用了一个 `Record` 结构体来存储每个记录的姓名、地址和学号，使用了文件读写来进行数据的存储和读取，使用了简单的插入、删除和修改操作来对记录进行更改。你可以根据需要进行修改和完善。