c语言写一个代码五子棋游戏

五子棋游戏是一种经典的策略性游戏，下面是使用C语言实现五子棋游戏的一个简单示例代码：

#include <stdio.h>

#define SIZE 15 // 棋盘大小

void init_board(char board[SIZE][SIZE]); // 初始化棋盘
void print_board(char board[SIZE][SIZE]); // 打印棋盘
int is_win(char board[SIZE][SIZE], char player, int x, int y); // 判断胜负
int player_move(char board[SIZE][SIZE], char player); // 玩家落子
int computer_move(char board[SIZE][SIZE], char computer); // 计算机落子

int main()
{
    char board[SIZE][SIZE]; // 棋盘数组
    char player = 'X'; // 玩家执棋
    char computer = 'O'; // 计算机执棋
    int turn = 0; // 回合数

    init_board(board); // 初始化棋盘

    while (1)
    {
        print_board(board); // 打印棋盘

        if (player_move(board, player)) // 玩家落子
        {
            printf("Player %c win!\n", player);
            break;
        }

        turn++;

        if (turn == SIZE * SIZE) // 判断平局
        {
            printf("Tie game!\n");
            break;
        }

        if (computer_move(board, computer)) // 计算机落子
        {
            printf("Computer %c win!\n", computer);
            break;
        }

        turn++;
    }

    return 0;
}

void init_board(char board[SIZE][SIZE])
{
    int i, j;

    for (i = 0; i < SIZE; i++)
    {
        for (j = 0; j < SIZE; j++)
        {
            board[i][j] = ' ';
        }
    }
}

void print_board(char board[SIZE][SIZE])
{
    int i, j;

    printf("   ");
    for (i = 0; i < SIZE; i++)
    {
        printf("%2d ", i + 1);
    }
    printf("\n");

    for (i = 0; i < SIZE; i++)
    {
        printf("%2d ", i + 1);
        for (j = 0; j < SIZE; j++)
        {
            printf("[%c]", board[i][j]);
        }
        printf("\n");
    }
}

int is_win(char board[SIZE][SIZE], char player, int x, int y)
{
    int i, j, k;
    int count;

    // 水平方向
    count = 1;
    for (i = x - 1; i >= 0 && board[y][i] == player; i--)
    {
        count++;
    }
    for (i = x + 1; i < SIZE && board[y][i] == player; i++)
    {
        count++;
    }
    if (count >= 5)
    {
        return 1;
    }

    // 竖直方向
    count = 1;
    for (i = y - 1; i >= 0 && board[i][x] == player; i--)
    {
        count++;
    }
    for (i = y + 1; i < SIZE && board[i][x] == player; i++)
    {
        count++;
    }
    if (count >= 5)
    {
        return 1;
    }

    // 左上到右下方向
    count = 1;
    for (i = x - 1, j = y - 1; i >= 0 && j >= 0 && board[j][i] == player; i--, j--)
    {
        count++;
    }
    for (i = x + 1, j = y + 1; i < SIZE && j < SIZE && board[j][i] == player; i++, j++)
    {
        count++;
    }
    if (count >= 5)
    {
        return 1;
    }

    // 左下到右上方向
    count = 1;
    for (i = x - 1, j = y + 1; i >= 0 && j < SIZE && board[j][i] == player; i--, j++)
    {
        count++;
    }
    for (i = x + 1, j = y - 1; i < SIZE && j >= 0 && board[j][i] == player; i++, j--)
    {
        count++;
    }
    if (count >= 5)
    {
        return 1;
    }

    return 0;
}

int player_move(char board[SIZE][SIZE], char player)
{
    int x, y;

    printf("Player %c's turn:\n", player);

    do
    {
        printf("Enter row and column numbers: ");
        scanf("%d %d", &y, &x);
        x--;
        y--;
        if (board[y][x] != ' ')
        {
            printf("Invalid move, try again.\n");
            continue;
        }
        board[y][x] = player;
        break;
    } while (1);

    return is_win(board, player, x, y);
}

int computer_move(char board[SIZE][SIZE], char computer)
{
    int x, y;

    printf("Computer %c's turn:\n", computer);

    do
    {
        x = rand() % SIZE;
        y = rand() % SIZE;

        if (board[y][x] != ' ')
        {
            continue;
        }

        board[y][x] = computer;
        break;
    } while (1);

    return is_win(board, computer, x, y);
}

这个代码使用了一个二维数组来表示棋盘，并通过逐个遍历来判断是否有五子连珠，玩家使用`X`作为棋子，计算机使用`O`作为棋子。玩家和计算机每次都在没有被占用的空位上下棋。