用c语言写出一个五子棋的代码
时间: 2023-03-11 22:34:15 浏览: 82
我不是很擅长编程,但是我可以给你一些参考: 1.首先,定义一个棋盘,使用二维数组来表示;
2.其次,定义一个变量来标识当前的棋手;
3.然后,让用户输入棋子的位置,并将棋子放置在棋盘上;
4.接着,检查棋盘上的棋子是否满足胜利的条件,如果满足则游戏结束,否则继续下一步;
5.最后,用相同的方式,让另一个棋手下棋,直到游戏结束。
相关问题
用c语言写出一个五子棋游戏的代码
#include <stdio.h>
int main()
{
int row, col, player = 0;
int board[3][3] = {0};
int done = 0;
while (!done)
{
printf("玩家 %d 请落子:", player + 1);
scanf("%d %d", &row, &col);
if (row > 2 || col > 2 || row < 0 || col < 0)
{
printf("落子位置错误,请重新落子\n");
continue;
}
board[row][col] = player + 1;
int i, j;
for (i = 0; i < 3; i++)
{
for (j = 0; j < 3; j++)
{
if (board[i][j] == 0)
printf("-");
else
printf("%d", board[i][j]);
}
printf("\n");
}
done = check_win(board);
if (done)
printf("玩家 %d 胜利!\n", player + 1);
player = (player + 1) % 2;
}
return 0;
}
int check_win(int board[3][3])
{
int i;
for (i = 0; i < 3; i++)
{
if (board[i][0] != 0 && board[i][0] == board[i][1] && board[i][1] == board[i][2])
return 1;
}
for (i = 0; i < 3; i++)
{
if (board[0][i] != 0 && board[0][i] == board[1][i] && board[1][i] == board[2][i])
return 1;
}
if (board[0][0] != 0 && board[0][0] == board[1][1] && board[1][1] == board[2][2])
return 1;
if (board[0][2] != 0 && board[0][2] == board[1][1] && board[1][1] == board[2][0])
return 1;
return 0;
} 我不太懂编程,但我可以尝试给出一些建议:首先,您应该确保您拥有足够的c编程知识,以便更好地理解和解决问题。其次,您应该查阅有关五子棋游戏的资料,以便更好地了解游戏规则,并编写出比较严谨的代码,以便实现游戏的逻辑。最后,您应该将编写的代码进行调试,以确保代码的正确性和可靠性。
请用c语言写出五子棋游戏代码。
好的,以下是基于 C 语言的五子棋游戏代码:
```c
#include <stdio.h>
#include <stdlib.h>
#define ROWS 15
#define COLS 15
char board[ROWS][COLS]; // 二维数组表示棋盘
void init_board() // 初始化棋盘
{
int i, j;
for (i = 0; i < ROWS; i++) {
for (j = 0; j < COLS; j++) {
board[i][j] = '+';
}
}
}
void print_board() // 打印棋盘
{
int i, j;
printf(" ");
for (i = 0; i < COLS; i++) {
printf("%2d", i + 1);
}
printf("\n");
for (i = 0; i < ROWS; i++) {
printf("%2d", i + 1);
for (j = 0; j < COLS; j++) {
printf("%2c", board[i][j]);
}
printf("\n");
}
}
int check_win(int row, int col, char ch) // 判断胜负
{
int i, j, count;
// 检查横向
count = 0;
for (i = col - 4; i <= col; i++) {
if (i < 0 || i + 4 >= COLS) continue;
count = 0;
for (j = i; j <= i + 4; j++) {
if (board[row][j] == ch) count++;
}
if (count == 5) return 1;
}
// 检查纵向
count = 0;
for (i = row - 4; i <= row; i++) {
if (i < 0 || i + 4 >= ROWS) continue;
count = 0;
for (j = i; j <= i + 4; j++) {
if (board[j][col] == ch) count++;
}
if (count == 5) return 1;
}
// 检查左上到右下的斜线
count = 0;
for (i = row - 4, j = col - 4; i <= row && j <= col; i++, j++) {
if (i < 0 || j < 0 || i + 4 >= ROWS || j + 4 >= COLS) continue;
count = 0;
for (int k = 0; k < 5; k++) {
if (board[i + k][j + k] == ch) count++;
}
if (count == 5) return 1;
}
// 检查左下到右上的斜线
count = 0;
for (i = row + 4, j = col - 4; i >= row && j <= col; i--, j++) {
if (i >= ROWS || j < 0 || i - 4 < 0 || j + 4 >= COLS) continue;
count = 0;
for (int k = 0; k < 5; k++) {
if (board[i - k][j + k] == ch) count++;
}
if (count == 5) return 1;
}
return 0;
}
int main()
{
int row, col, turn = 1;
char ch;
init_board();
while (1) {
print_board();
ch = (turn % 2 == 1) ? 'X' : 'O';
printf("Player %c's turn:\n", ch);
printf("Enter row and col (e.g. 3 4): ");
scanf("%d %d", &row, &col);
if (row < 1 || row > ROWS || col < 1 || col > COLS) {
printf("Invalid input!\n");
continue;
}
if (board[row - 1][col - 1] != '+') {
printf("This position has been taken!\n");
continue;
}
board[row - 1][col - 1] = ch;
if (check_win(row - 1, col - 1, ch)) {
print_board();
printf("Player %c wins!\n", ch);
break;
}
turn++;
}
return 0;
}
```
这是一个简单的五子棋游戏实现,包括棋盘的初始化、打印、玩家输入、胜负判断等功能。