import java.util.Scanner; public class StonePile { public static void main(String args[]) { int len; int a = 0; int sum = 0; int result = 0; int b=0; Scanner scan = new Scanner(System.in);len= Integer.parseInt(scan.nextLine()); String str = scan.nextLine(); String[] numstr = str.split(" "); int[] num = new int[len]; for ( b = 0; b < len; b++) { num[b] = Integer.parseInt(numstr[b]); sum+=num[b]; } int[][] dp = new int[2][sum / 2 + 1]; for (int j = 0; j <= sum / 2; j++) { dp[0][j] = j >= num[0] ? num[0] : 0; } for (int i = 1; i < len; i++) { for (int j = 0; j <= sum / 2; j++) { int x = dp[i - 1&1][j]; int y = j >= num[i] ? dp[i - 1&1][j - num[i]] + num[i] : 0; dp[i&1][j] = Math.max(x, y); } } result = (sum - dp[(len - 1)&1][sum / 2]) - dp[(len - 1)&1][sum / 2]的计算复杂度

浙大-Java语言程序的设计编程答案10.doc

public static void main(String[] args) { int ri, repeat, count, word, i; String line; char c; Scanner in = new Scanner(System.in); repeat = (in.nextLine()).charAt(0) - '0'; for (ri = 1; ri <= ...

华为OD机试C卷- 中文分词模拟器（Java & JS & Python & C）.md-私信看全套OD代码及解析

public static void main(String[] args) { Scanner scanner = new Scanner(System.in); String sentence = scanner.nextLine(); String dictionaryStr = scanner.nextLine(); Set<String> dictionary = new ...

import java.util.ArrayList; import java.util.Arrays; import java.util.Scanner; public class 1322 { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); String str = sc.next(); char []chars=str.toCharArray(); char []result=spy(n,chars); System.out.println(result); } public static char[] spy(int n,char[] chars){ int len=chars.length; ArrayList<Integer>[] ch = new ArrayList[128]; for (int i = 0; i < 128; i++) { ch[i] = new ArrayList<Integer>(); } for (int i = 0; i < chars.length; i++) { ch[chars[i]].add(i); } int[]next=new int[len]; int count=0; for (int i = 0; i < 128; i++) { for (int num : ch[i]) { next[count++]=num; } } char[] result=new char[len]; int index=n-1; for (int i = 0; i < len; i++) { result[i] = chars[index=next[index]]; } return result; } }解释这段代码并说出他的计算复杂度

这段代码实现了一种加密算法，输入一个整数n和一个字符串str，输出将str按照一定规则加密后的结果。具体实现是将字符串中的每个字符按照ASCII码值存储在一个ArrayList数组中，然后按照存储顺序重新排列，最后按照...

import java.util. *; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in ); int n = sc.nextInt(); int[] ints = new int[n]; for (int i = 0; i < n; i++) { ints[i] = sc.nextInt(); } int res = 0; for (int i = 1; i < ints.length; i++) { int add = ints[i] + ints[i - 1]; if (add < 100) { res += 100 - add; } } System.out.println(res); } }，换成python输出

Here's the Python code equivalent to the Java code you provided: python n = int(input()) ints = list(map(int, input().split())) res = 0 for i in range(1, len(ints)): add = ints[i] + ints[i - 1] ...

package codefinal; import java.io.InputStream; import java.util.Scanner; import java.io.File; import java.io.FileInputStream; import java.io.IOException; public class homework { public static void main(String[] args)throws Exception { Scanner r=new Scanner(System.in); System.out.println("输入第一个文件的路径及文件名"); String f1=r.next(); System.out.println("输入第二个文件的路径及文件名"); String f2=r.next(); File file1=new File(f1); File file2=new File(f2); FileInputStream is=new FileInputStream(f1); if(f1.length()==f2.length()) System.out.println("两个文件长度相同"); byte[] buffer1=new byte[3]; byte[] buffer2=new byte[3]; int len1; int len2; int a=0; while( (len1=is.read(buffer1))!=-1&&(len2=is.read(buffer2))!=-1){ String rs1=new String(buffer1,0,len1); String rs2=new String(buffer2,0,len2); if(rs1!=rs2) { System.out.println("两个文件内容不相同"); a=-1; break; } if(a==0) System.out.println("两个文件内容相同"); } } }这代码语法有问题嘛

这段代码的语法没有问题，但是在文件比较的逻辑上有一些问题。具体来说，以下几点需要注意： 1. 文件长度相同并不意味着文件内容相同，因此只比较文件长度并不能判断两个文件是否相同。 2. 在比较文件内容时，应该...

package net; import java.io.; import java.net.; import java.util.Scanner; public class Client { public static final String SERVER_IP = "127.0.0.1"; public static final int SERVER_PORT = 8080; public static void main(String[] args) throws Exception { Socket socket = new Socket(SERVER_IP, SERVER_PORT); System.out.println("Connection established."); Scanner input=new Scanner(System.in,"GBK"); System.out.println("input your file:");//输入的要是文件的全名（包括后缀）和路径 //D:/Javawork/实验文件/计网实验/hello.txt String fileName = input.nextLine(); OutputStream out = socket.getOutputStream(); PrintWriter pw = new PrintWriter(out); pw.println(fileName); // 发送文件名 pw.flush(); InputStream in = new FileInputStream(fileName); byte[] buffer = new byte[1024]; int len = 0; while ((len = in.read(buffer)) != -1) { out.write(buffer, 0, len); } in.close(); out.close(); socket.close(); System.out.println(fileName + " is sent."); } }

这是一个 Java 的客户端程序，用于向指定的 IP 地址和端口号的服务器文件。客户端程序首先建立与服务器的 Socket 连接，然后要求用户输入要发送的文件名（包括路径），并将其发送给服务器。接下来，客户端程序将文件...

解释一下这段代码并说出它的计算复杂度import java.util.Arrays; import java.util.Scanner; public class p1160 { static class Node implements Comparable<Node> { int x, y, len; public Node(int x, int y, int len) { this.x = x; this.y = y; this.len = len; } @Override public int compareTo(Node other) { return Integer.compare(this.len, other.len); } } static int[] fa; static int find(int x) { if (fa[x] != x) fa[x] = find(fa[x]); return fa[x]; } public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int n = scanner.nextInt(); int m = scanner.nextInt(); fa = new int[n + 1]; for (int i = 1; i <= n; i++) fa[i] = i; Node[] p = new Node[m + 1]; for (int i = 1; i <= m; i++) { int x = scanner.nextInt(); int y = scanner.nextInt(); int len = scanner.nextInt(); p[i] = new Node(x, y, len); } Arrays.sort(p, 1, m + 1); int s = 0, maxz = 0; int i; for (i = 1; i <= m && s < n - 1; i++) { int tx = find(p[i].x); int ty = find(p[i].y); if (tx != ty) { fa[tx] = ty; s++; maxz = Math.max(maxz, p[i].len); } } System.out.println(maxz); System.out.println(i - 1); for (int j = 1; j < i; j++) System.out.println(p[j].x + " " + p[j].y); } }

接下来m行每行包含三个整数x、y、len，表示点x和点y之间有一条长度为len的边。程序会输出最小生成树的最大边权值，以及最小生成树的所有边。该算法的时间复杂度为O(mlogm)，其中m是边的数量。主要由于排序的时间...

import java.util.Scanner; public class Fools { public static void main(String[] args) { int len; int b = 0; int sum = 0; Scanner scan = new Scanner(System.in); len = Integer.parseInt(scan.nextLine()); String str = scan.nextLine(); String[] numstr = str.split(" "); int[] arr = new int[len]; for (b = 0; b < len; b++){ arr[b] = Integer.parseInt(numstr[b]); sum += arr[b];} for(int a=sum;a>0;a=a-2) { int max = 0; for (int i = 1; i <= arr.length - 1; i++) { if (arr[max] < arr[i]) { max = i; } } int min = max; for (int i =arr.length-1 ; i >=0; i--) { if ((arr[min] > arr[i] &&arr[i]>0)||(min==max&&arr[i]>0)){ min = i;} } System.out.print(max+1+" "); arr[max]--; if(arr[min]>0){ System.out.print(min+1+" "); arr[min]--; } } } }解释这段代码运行过程

- 玩家按照分数从高到低依次进行游戏，每次游戏可以选择一个分数不为 0 的玩家进行操作，将其分数减 1，然后再选择一个分数不为 0 的玩家进行操作，将其分数减 1； - 游戏结束的条件是所有玩家的分数都为 0。代码...

修正以下代码：import java.io.*; import java.net.ServerSocket; import java.net.Socket; import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class Sever { // 保存所有用户的用户名和密码 private static Map<String, String> userMap = new HashMap<>(); // 指定的目录 private static File rootDir = null; // 保存所有登录的用户信息 private static Map<String, String> loginInfo = new HashMap<>(); public static void main(String[] args) throws Exception { // 从配置文件中读取用户信息和目录信息 BufferedReader reader = new BufferedReader(new FileReader("config.txt")); String line = null; while ((line = reader.readLine()) != null) { if (line.startsWith("user:")) { String[] user = line.split(":"); userMap.put(user[1], user[2]); } if (line.startsWith("dir:")) { String[] dir = line.split(":"); rootDir = new File(dir[1]); } } reader.close(); // 启动服务器 ServerSocket serverSocket = new ServerSocket(8000); int count = 0; System.out.println("服务器启动成功！"); while (true) { // 监听客户端连接 Socket socket = serverSocket.accept(); count++; System.out.println("第" + count + "个客户端连接成功！"); // 处理客户端请求 new Thread(new ServerThread(socket)).start();

public static void main(String[] args) throws Exception { // 从配置文件中读取用户信息和目录信息 BufferedReader reader = new BufferedReader(new FileReader("config.txt")); String line = null; while...

import java.util.*; public class 1806 { static int n; static int[] t = new int[10]; static int[] telegraph = new int[50005]; static int[] dis = new int[50005]; static int[] pre = new int[50005]; static boolean[] vis = new boolean[50005]; static ArrayList<Integer> path = new ArrayList<Integer>(); public static void main(String[] args) { Scanner sc = new Scanner(System.in); n = sc.nextInt(); for (int i = 0; i < 10; i++) { t[i] = sc.nextInt(); } for (int i = 1; i <= n; i++) { telegraph[i] = sc.nextInt(); } dijkstra(1); if (dis[n] == Integer.MAX_VALUE) { System.out.println("-1"); } else { System.out.println(dis[n]); getPath(n); System.out.println(path.size()); for (int i = 0; i < path.size(); i++) { System.out.print(path.get(i) + " "); } } } private static void dijkstra(int s) { Arrays.fill(dis, Integer.MAX_VALUE); dis[s] = 0; for (int i = 1; i <= n; i++) { pre[i] = i; } for (int k = 0; k < n; k++) { int u = -1; int minDis = Integer.MAX_VALUE; for (int i = 1; i <= n; i++) { if (!vis[i] && dis[i] < minDis) { u = i; minDis = dis[i]; } } if (u == -1) { break; } vis[u] = true; for (int i = 1; i <= n; i++) { if (!vis[i]) { int w = getWeight(telegraph[u], telegraph[i]); if (dis[u] + w < dis[i]) { dis[i] = dis[u] + w; pre[i] = u; } } } } } private static int getWeight(int a, int b) { int weight = 0; String s1 = String.valueOf(a); String s2 = String.valueOf(b); int len = Math.min(s1.length(), s2.length()); for (int i = 0; i < len; i++) { if (s1.charAt(i) != s2.charAt(i)) { weight = t[i]; break; } } return weight; } private static void getPath(int u) { if (u != 1) { getPath(pre[u]); } path.add(u); } }解释一下该代码的运行过程

这段代码实现了一个基于Dijkstra算法的最短路径问题求解，输入的数据包括电报码的位数n，每个数字所需的时间t[i]，以及n个电报码。程序首先调用dijkstra函数，计算从起点1到终点n的最短路径，同时记录每个节点的前驱...

将下面java代码改为python代码 import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); JinCheng process1 = new JinCheng(); JinCheng process2 = new JinCheng(); JinCheng process3 = new JinCheng(); JinCheng[] processes = {process1,process2,process3}; for (JinCheng process : processes) { process.name = scanner.next(); process.enterTime = scanner.nextInt(); process.runningTime = scanner.nextInt(); } int i=0; while(i < processes.length - 1) { int j = 0; while(j < processes.length -1 - i) { if (processes[j+1].enterTime < processes[j].enterTime) { JinCheng tmp = processes[j]; processes[j] = processes[j+1]; processes[j+1] = tmp; } j++; } i++; } zgxyb_sf(processes); System.out.println(process1.zzsj + " " + process2.zzsj + " " + process3.zzsj); } private static void zgxyb_sf(JinCheng[] processes) { processes[0].startTime = processes[0].enterTime; processes[0].jssj = processes[0].startTime+processes[0].runningTime; processes[1].responseRatio = 1 + (float)(processes[0].jssj- processes[1].enterTime)/(processes[1].runningTime); processes[2].responseRatio = 1 + (float)(processes[0].jssj - processes[2].enterTime)/(processes[2].runningTime); if (processes[1].responseRatio < processes[2].responseRatio) { if (processes[2].enterTime > processes[0].jssj) { processes[2].startTime = processes[2].enterTime; processes[2].jssj = processes[2].startTime + processes[2].runningTime; if (processes[1].enterTime > processes[2].jssj) { processes[1].startTime = processes[1].enterTime; }else { processes[1].jssj = processes[2].jssj; } processes[1].jssj= processes[1].startTime + processes[1].runningTime; }else { processes[2].startTime = processes[0].jssj; processes[2].jssj = processes[2].startTime + processes[2].runningTime; if (processes[2].jssj < processes[1].enterTime) { processes[1].startTime = processes[1].enterTime; }else { processes[1].startTime = processes[2].jssj; } processes[1].jssj= processes[1].startTime + processes[1].runningTime; } }else { if (processes[1].enterTime > processes[0].jssj) { processes[1].startTime = processes[1].enterTime; processes[1].jssj = processes[1].startTime + processes[1].runningTime; if (processes[2].enterTime > processes[1].jssj) { processes[2].startTime = processes[2].enterTime; }else { processes[2].startTime = processes[1].jssj; } processes[2].jssj = processes[2].startTime + processes[2].runningTime; }else { processes[1].startTime = processes[0].jssj; processes[1].jssj = processes[1].startTime + processes[1].runningTime; if (processes[2].enterTime > processes[1].jssj) { processes[2].startTime = processes[2].enterTime; }else { processes[2].startTime = processes[1].jssj; } processes[2].jssj = processes[2].startTime + processes[2].runningTime; } } processes[0].zzsj = processes[0].jssj - processes[0].enterTime; processes[1].zzsj =processes[1].jssj - processes[1].enterTime; processes[2].zzsj =processes[2].jssj - processes[2].enterTime; } } class JinCheng{ public String name; public int enterTime; public int runningTime; public int startTime; public int jssj; public float responseRatio; public int zzsj; }

以下是将Java代码翻译成Python代码的结果： python class JinCheng: def __init__(self): self.name = "" self.enterTime = 0 self.runningTime = 0 self.startTime = 0 self.jssj = 0 self....

Exception in thread "Thread-1" java.lang.IllegalStateException: Scanner closed at java.base/java.util.Scanner.ensureOpen(Scanner.java:1150) at java.base/java.util.Scanner.next(Scanner.java:1573) at java.base/java.util.Scanner.nextInt(Scanner.java:2258) at java.base/java.util.Scanner.nextInt(Scanner.java:2212) at my_project/myproject.Client.lambda$1(Client.java:52) at java.base/java.lang.Thread.run(Thread.java:833) java.net.SocketException: Socket closed at java.base/sun.nio.ch.NioSocketImpl.endRead(NioSocketImpl.java:248) at java.base/sun.nio.ch.NioSocketImpl.implRead(NioSocketImpl.java:327) at java.base/sun.nio.ch.NioSocketImpl.read(NioSocketImpl.java:350) at java.base/sun.nio.ch.NioSocketImpl$1.read(NioSocketImpl.java:803) at java.base/java.net.Socket$SocketInputStream.read(Socket.java:966) at java.base/java.io.InputStream.read(InputStream.java:218) at my_project/myproject.Client.lambda$0(Client.java:33) at java.base/java.lang.Thread.run(Thread.java:833)

public static void main(String[] args) { Client client = new Client(); client.start(); } } 在修改后的代码中，我们将接收服务器发送消息的逻辑移到了主线程中，并在最后关闭了Socket连接。这样就避免...

while True: n=int(input()) a=list(map(int,input().split())) sum=0 a.sort() for i in range(0,len(a)-1): sum+=a[i]*(len(a)-i-1) m=sum/n print('%.2f'%m)转为java代码

public static void main(String[] args) { Scanner scanner = new Scanner(System.in); while (true) { int n = scanner.nextInt(); if (n == 0) { break; } int[] a = new int[n]; for (int i = 0; i ; i...

#include <stdio.h> #include <string.h> #define MAXSIZE 10011 int n, ans, k, coe, len, outcome, c[MAXSIZE]; char e[MAXSIZE], s[MAXSIZE]; void sort(int x) { int i, j, t; for(i = 1; i < x; i ++){ for(j = i+1; j > 1; j--){ if(c[j] < c[j-1]){ t = c[j-1]; c[j-1] = c[j]; c[j] = t; }else{ break; } } } } int calculate() { int i, j; k = outcome = 0; strcpy(s, e); len = strlen(s); if(s[0] != '-'){ for(i = len + 1; i > 0; i --){ s[i] = s[i-1]; } s[0] = '+'; len ++; } for(i = 0; i < len; i += 3){ if(s[i] == '+'){ coe = 1; }else{ coe = -1; } i ++; j = 0; while('0' <= s[i] && s[i] <= '9'){ j = 10; j += s[i++] - '0'; } if(s[i] == ''){ i ++; }else{ j = 1; } coe = j; c[++k] = coe; outcome += (n-(s[i] == 'a')) coe; } sort(k); for(i = 1; i <= k; i ++){ outcome += i * c[i]; } return outcome; } int main() { scanf("%d %s", &n, e); ans = calculate(); printf("%d\n", ans); return 0; }把这个转化成java代码

public static void main(String[] args) { Scanner sc = new Scanner(System.in); n = sc.nextInt(); e = sc.next().toCharArray(); ans = calculate(); System.out.println(ans); sc.close(); } static ...

要求使用Java语言，要用到 int n; char str[10000]; int len=strlen(str);来实现简单排序输入任意一串数字，实现简单排序。

public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print("请输入数字串："); String str = scanner.nextLine(); int len = str.length(); int[] arr = new ...

要求实现简单排序输入任意一串数字，实现简单排序描述数据的存储的定义。要求 int n; char str[10000]; int len=strlen(str);用Java实现

public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print("请输入数字个数："); int n = scanner.nextInt(); int[] arr = new int[n]; System.out.print("请...

用java编写一个函数 int same_set(int a[],int b[],int len)，该函数检查相等长度的两个数组是否包含相同的元素,若包含相同的元素, 则返回1,否则返回0,其中参数len是数组a与与数组b的元素个数。不考虑元素的顺序，如果元素重复，重复次数也相同。在main函数中读入两个整数数组,测试该函数

public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int n = scanner.nextInt(); int[] a = new int[n]; for (int i = 0; i ; i++) { a[i] = scanner.nextInt(); } int[]...

编写一个java函数 int same_set(int a[],int b[],int len)，该函数检查相等长度的两个数组是否包含相同的元素,若包含相同的元素, 则返回1,否则返回0,其中参数len是数组a与与数组b的元素个数。不考虑元素的顺序，如果元素重复，重复次数也相同。在main函数中读入两个整数数组,测试该函数。【输入形式】从键盘输入两个数组，第一行输入数组元素个数，第二行输入第一个数组的各个值，第三行输入第二个数组的各个值。【输出形式】如果两个数组包含的元素相同，打印1，否则，打印0。

public static void main(String[] args) { Scanner scanner = new Scanner(System.in); // 读取第一个数组 int len = scanner.nextInt(); int[] a = new int[len]; for(int i = 0; i < len; i++) { a[i] =...

java编程① 类ArraysApps，用于数组操作，包含下面4个方法： ★ int selMin(int[] arr1); //返回一维数组中的最小数 ★ void delete(int[] arr); //先对一维数组升序排序，再删除相同元素 ★ void insert(int[] arr,int le,int x); //先对一维数组arr（数组长度为len）升序排序，再插入元素x，并输出插入元素后的数组结果，以及所有元素的平均值（保留两位小数） ★ int[] arrSum(int[][] arr2); //求二维数组每一行的元素之和 ② 主类，用于声明一个一维数组、二维数组，并输入两个数组的元素的值，然后调用类ArraysApps的4个方法后得到相应的结果并输出

public static void main(String[] args) { Scanner input = new Scanner(System.in); //声明一个一维数组并输入元素的值 System.out.print("请输入一维数组的长度："); int len = input.nextInt(); int[] ...

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要求使用Java语言，要用到 int n; char str[10000]; int len=strlen(str);来实现简单排序 输入任意一串数字，实现简单排序。

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要求使用Java语言，要用到 int n; char str[10000]; int len=strlen(str);来实现简单排序输入任意一串数字，实现简单排序。

要求实现简单排序输入任意一串数字，实现简单排序描述数据的存储的定义。要求 int n; char str[10000]; int len=strlen(str);用Java实现